Question

我有两个图像文件夹，我正在尝试从每个文件夹中的所有切片构建一个大图像。我需要在文件夹之间交替来构建图像。例如，第一个切片来自文件夹1，第二个切片来自文件夹2，第三个来自文件夹1等。我在各个文件夹中按文件名排序文件，因此我试图遍历文件夹并向图像添加新条带。代码运行但它似乎没有保存合成图像。我是PIL的新手，所以我确信这很简单，但感谢您的帮助。谢谢！

def merge_images(file1, file2):
   """Merge two images into one, displayed above and below
   :param file1: path to first image file
   :param file2: path to second image file
   :return: the merged Image object
   """

   if file1.startswith('.'):
       return None

   image1 = Image.open(file1)
   image2 = Image.open(file2)

   (width1, height1) = image1.size
   (width2, height2) = image2.size

   result_width = width1 + width2
   result_height = max(height1, height2)

   result = Image.new('RGB', (result_width, result_height))
   result.paste(im=image1, box=(0, 0))
   result.paste(im=image2, box=(0, height1))

   return result

imageCounter = 0
firstPass = True
compImage = Image.new('RGBA', img.size, (0,0,0,0))

for i in range(len(boundingBoxes)+1):
    if firstPass:
        compImage = merge_images('./image_processing/'+ os.listdir('./image_processing/')[imageCounter],
        './img_patches/outputs/'+os.listdir('./img_patches/outputs/')[imageCounter])


        if compImage is not None:
            firstPass = False

            compImage.save('./image_processing/compImage.jpg')


    else:
        compImage = merge_images('./image_processing/compImage.jpg','./image_processing/'+ os.listdir('./image_processing/')[imageCounter])

        compImage.save('./image_processing/compImage.jpg')
        compImage = merge_images('./image_processing/compImage.jpg','./img_patches/outputs/'+ os.listdir('./img_patches/outputs/')[imageCounter])

        compImage.save('./image_processing/compImage.jpg')

    imageCounter = imageCounter + 1

Answer 1

你必须告诉PIL保存图像：

for i in range(len(boundingBoxes)+1):
    if firstPass:
        compImage = merge_images('./image_processing/'+ os.listdir('./image_processing/')[imageCounter],
        './img_patches/outputs/'+os.listdir('./img_patches/outputs/')[imageCounter])
        compImage.save(open('output/{}.png'.format(imageCounter), 'w'))

在PIL Python

1 个答案: