我使用jquery数据表来显示我从jsonresponse获得的数据。 表的初始显示是可以的,但是当我点击刷新并使用
时$('#search-notable-authors').DataTable().destroy();
$('#search-notable-authors').DataTable(
它会重新加载表格,但重复标题图标的次数是我点击刷新按钮的次数。
这是完整的jq代码
<script type="text/javascript">
var $jquery_1_11_3 = jQuery.noConflict(true);
(function ($) {
$(document).ready(function () {
$("#refresh-btn").on("click",function(){
showItemsTable1();
});
ajaxPaths = {
allNotableAuthors: "{{ path('json_getAllNotableAuthors') }}",
allNotableAuthorsByJournal: "{{ path('json_getAllNotableAuthorsByJournal') }}"
},
itemsTable = null,
getItems = function () {
return $.Deferred(function () {
var that = this;
$.ajax({
type: "POST",
data: $('#articlesList').serialize(),
url: ajaxPaths.allNotableAuthors,
success: function (data) {
console.log(data);
that.resolve(data);
}
});
});
},
getItems1 = function () {
return $.Deferred(function () {
var that = this;
var journal = $("#search_authors_name_short").val();
$.ajax({
type: "POST",
data: { term : journal },
url: ajaxPaths.allNotableAuthorsByJournal,
success: function (data) {
console.log(data);
that.resolve(data);
}
});
});
},
showItemsTable = function () {
return $.Deferred(function () {
var that = this;
getItems().done(function (itemsData) {
$('#search-notable-authors').DataTable({
aLengthMenu: [
[25, 50, 100, 200, -1],
[25, 50, 100, 200, "All"]
],
iDisplayLength: -1,
data: itemsData,
columns: [
{"data": 0},
{"data": 1},
{"data": 2},
{"data": 3},
{"data": 4}
]
});
that.resolve();
});
});
},
showItemsTable1 = function () {
return $.Deferred(function () {
var that = this;
getItems1().done(function (itemsData) {
$('#search-notable-authors').DataTable().destroy();
$('#search-notable-authors').DataTable({
aLengthMenu: [
[25, 50, 100, 200, -1],
[25, 50, 100, 200, "All"]
],
iDisplayLength: -1,
data: itemsData,
columns: [
{"data": 0},
{"data": 1},
{"data": 2},
{"data": 3},
{"data": 4}
]
});
that.resolve();
});
});
}
showItemsTable();
});//end of doc ready
})($jquery_1_11_3);
</script>
如何在不重复标题图标的情况下解决此问题?
答案 0 :(得分:0)
我没有找到问题的原因,所以我没有修复它,但我找到了绕过它的解决方案。所以这就是我要做的事情,直到找到更好的东西。
在脚本开始时,我从表头获取html,如下所示:
var hdr = $('#search-notable-authors').find('thead').html();
然后在showItemsTable中我销毁并清空表
var tableId = $('#search-notable-authors');
itemsTable = $(tableId).DataTable();
itemsTable.destroy();
$(tableId).empty();
然后用表格
替换html$('#search-notable-authors').find('thead').html(hdr);
这是完整的showItemsTable代码:
showItemsTable = function () {
return $.Deferred(function () {
var that = this;
getItems().done(function (itemsData) {
var tableId = $('#search-notable-authors');
var header = $(tableId).find('thead').html();
itemsTable = $(tableId).DataTable();
itemsTable.destroy();
$(tableId).empty();
itemsTable = $(tableId).DataTable({
aLengthMenu: [
[25, 50, 100, 200, -1],
[25, 50, 100, 200, "All"]
],
iDisplayLength: -1,
data: itemsData,
columns : [
DataTables.expandCol,
{"data": 'id'},
{"data": 'email'},
{"data": 'journal'},
{"data": 'title'},
{"data": 'citation_link'}
]
});
$('#search-notable-authors').find('thead').html(hdr);
that.resolve();
});
});
},
如果有人提出更好的解决方案,或解决原始问题,请写下