Question

数据集：

foo.Y

我想基于CreatedAt列对上述数据进行分组，并根据数据集中的 new_repeat 列过滤数据。我已经为此编写了一个函数，它使用_.chain并对数据进行分组，但我无法对其进行过滤。检查以下功能：

[
  {
    "created_by": "5750790484393984",
    "patient_dateofbirth": "02/05/1990",
    "patient_aadhaar": "1234567890",
    "patient_area": "wert",
    "patient_state": "Arunachal Pradesh",
    "patient_gender": "Male",
    "patient_pincode": "123456",
    "location": "Guwahati",
    "patient_name": "Rakesh",
    "isVisited": 2,
    "new_repeat": "Repeat",
    "lastVisitDate": "2017-07-04",
    "updatedAt": "2017-07-04T04:41:59.261Z",
    "CreatedAt": "2017-07-03T18:48:25.773Z",
    "patient_bloodgroup": "B+",
    "patient_country": "India"
  },
  {
    "created_by": "5750790484393984",
    "patient_dateofbirth": "07/30/2006",
    "patient_aadhaar": "2343524361731",
    "patient_area": "begusarai",
    "patient_state": "Bihar",
    "patient_gender": "Male",
    "patient_pincode": "110016",
    "patient_name": "gyguy yuguy",
    "registration_number": "2",
    "ip_address": "43.225.248.20, 162.158.155.110",
    "CreatedAt": "2017-06-28T09:41:47.188Z",
    "patient_bloodgroup": "A+",
    "patient_country": "India"
  },
  {
    "ip_address": "103.83.148.161, 141.101.99.35",
    "lastVisitDate": "2017-07-04",
    "updatedAt": "2017-07-04T09:56:51.588Z",
    "CreatedAt": "2017-07-02T23:37:29.512Z",
    "patient_bloodgroup": "A+",
    "patient_country": "India",
    "created_by": "5750790484393984",
    "patient_dateofbirth": "06/24/1964",
    "patient_aadhaar": "",
    "patient_area": "Chattarpur",
    "patient_state": "Uttar Pradesh",
    "patient_gender": "Female",
    "patient_pincode": "201005",
    "patient_name": "Sudha Ambastha",
    "isVisited": 2,
    "new_repeat": "Repeat"
  },
  {
    "patient_area": "ajsdh",
    "patient_state": "Delhi",
    "patient_gender": "Male",
    "patient_pincode": "110074",
    "patient_name": "prashant",
    "registration_number": "283423472834",
    "isVisited": 1,
    "new_repeat": "New",
    "ip_address": "43.225.248.20, 162.158.155.110",
    "lastVisitDate": "2017-07-04",
    "updatedAt": "2017-07-03T18:41:55.777Z",
    "CreatedAt": "2017-06-28T11:18:55.792Z",
    "patient_bloodgroup": "B+",
    "patient_country": "India",
    "created_by": "5750790484393984",
    "patient_dateofbirth": "06/13/1990",
    "patient_aadhaar": "2131231238"
  },
  {
    "created_by": "5750790484393984",
    "patient_dateofbirth": "06/07/1990",
    "patient_aadhaar": "1278292020029",
    "patient_area": "Bhubneshwar",
    "patient_state": "Orissa",
    "patient_gender": "Male",
    "patient_pincode": "112218",
    "location": "Haldia",
    "patient_name": "Rajesh Mishra",
    "isVisited": 2,
    "new_repeat": "Repeat",
    "lastVisitDate": "2017-07-04",
    "updatedAt": "2017-07-04T04:40:26.724Z",
    "CreatedAt": "2017-07-03T04:21:35.647Z",
    "patient_bloodgroup": "B-",
    "patient_country": "India"
  }
]

group_by是日期格式，可以是＆＃34; DD-MM-YYYY＆＃34;或者＆＃34; MMM＆＃34; 所以，上面是函数。如何过滤参数和值。

请建议更改：

const formatDataCount = (data, group_by) => {
  return  _.chain(data)
    .sortBy('CreatedAt')
    .groupBy(datum => moment(datum.CreatedAt).format(group_by) )
    .map((value, key) => {
      return {
        label: key, 
        value:  _.size(value)
      }
    })
    .value();
};

第一个是工作，第二个是没有。

Answer 1

过滤行 - .filter(filter_by => filter_by.new_repeat == "New")应位于groupBy之前。我还会将其移到sortBy，因为您不需要对要删除的数据进行排序。

const formatDataCount = (data, group_by) => {
  return  _.chain(data)
    .filter(filter_by => filter_by.new_repeat == "New")
    .sortBy('CreatedAt')
    .groupBy(datum => moment(datum.CreatedAt).format(group_by) )
    .map((value, key) => {
      return {
        label: key, 
        value:  _.size(value)
      }
    })
    .value();
};

在lodash中使用_.chain .groupBy .filter .map来根据不同的过滤器进行分组

1 个答案: