如何将std::string
转换为boost::asio::streambuf
?
任何领导都表示赞赏。
最初我使用boost::asio::read_until(pNetworkConnector->getSocket(), response, "\r\n");
初始化boost::asio::streambuf response
并将其转换为基础流,即
boost::asio::streambuf* responsePointer = &response;
iResponseStream.rdbuf(responsePointer);
但现在我直接使用像这样的curl std::string
static size_t WriteCallback(void* contents, size_t size, size_t nmemb, void* userp)
{
((std::string*)userp)->append((char*)contents, size * nmemb);
return size * nmemb;
}
并将其用作
curl_easy_setopt(handle, CURLOPT_WRITEFUNCTION, WriteCallback);
curl_easy_setopt(handle, CURLOPT_WRITEDATA, &readBuffer);
如何将std::string
转换为boost::asio::streambuf
或std::streambuf
?
答案 0 :(得分:2)
以下代码显示了如何在std::string
和boost::asio::streambuf
之间进行转换,请参见online at ideone:
#include <iostream>
#include <boost/asio/streambuf.hpp>
#include <boost/asio/buffer.hpp>
int main()
{
/* Convert std::string --> boost::asio::streambuf */
boost::asio::streambuf sbuf;
std::iostream os(&sbuf);
std::string message("Teststring");
os << message;
/* Convert boost::asio::streambuf --> std::string */
std::string str((std::istreambuf_iterator<char>(&sbuf)),
std::istreambuf_iterator<char>());
std::cout << str << std::endl;
}