Question

$sql="INSERT INTO prescription
      (username,phone,procedure,address,emailid,reviews,followups,nextappointment)
      VALUES
      ("$username","$phone","$procedure","$address","$emailid","$reviews",$followups,"$nextappointment")";

Answer 1

我认为你的问题在引号中，你在双引号内有双引号，你应该转义引号或使用单引号。

简单易用的是使用准备好的陈述。

我不确定您使用PDO / MSQLI的哪个API

如果您在PDO中：

SELECT  z.zip AS [ZIP] ,
        z.city AS [City] ,
        z.state AS [State] ,
        z.county AS [County] ,
        lp.value AS [Geomarket Short] ,
        lp2.value AS [Geomarket Long]
FROM    world.dbo.zip z
        LEFT OUTER JOIN [lookup.prompt] lp ON lp.index = z.zip
                                              AND lp.key = 'geomarket_zip'
        LEFT OUTER JOIN [lookup.prompt] lp2 ON lp.value = lp2.index
                                               AND lp2.key = 'geomarket'
ORDER BY z.zip;

如果你在mysqli上，那么：

<?php

$sql =$databaseConnectionVar->prepare("INSERT INTO prescription(username,phone,procedure,address,emailid,reviews,followups,nextappointment)VALUES(?,?,?,?,?,?,?,?)")
        ->execute(array($username,$phone,$procedure,$address,$emailid,$reviews,$followups,$nextappointment));

if(!$sql){

    print_r($databaseConnectionVar->errorInfo());
}else{

    echo "data inserted";
}
?>

然后您需要查看重要的链接：

How to get mysqli error in different environments?
When to use single quotes, double quotes, and backticks in MySQL
When should I use prepared statements?
Prepared Statements

希望这会指向正确的道路。

Answer 2

您应该更改“”是否知道应该更改单引号''。

例如下面：

$sql = 'INSERT INTO prescription(username,phone,procedure,address,emailid,reviews,followups,nextappointment)
    VALUES("$username","$phone","$procedure","$address","$emailid","$reviews",$followups,"$nextappointment")';

希望它会帮助你

Answer 3

你的引号错了，在值中使用单引号（''），您的IDE出错了。或者如果你只是复制并运行数据库。

   mTitle = mDrawerTitle = getTitle();
        mPlanetTitles = getResources().getStringArray(R.array.planets_array);
        mDrawerLayout = (DrawerLayout) findViewById(R.id.drawer_layout);
        mDrawerList = (ListView) findViewById(R.id.left_drawer);

        mDrawerLayout.setDrawerShadow(R.drawable.drawer_shadow, GravityCompat.START);
        // set up the drawer's list view with items and click listener
        mDrawerList.setAdapter(new ArrayAdapter<String>(this,
                R.layout.drawer_list_item, mPlanetTitles));
        mDrawerList.setOnItemClickListener(new DrawerItemClickListener());

       mDrawerList.setOnItemClickListener(new DrawerItemClickListener());

        // enable ActionBar app icon to behave as action to toggle nav drawer
        /*getActionBar().setDisplayHomeAsUpEnabled(false);
        getActionBar().setHomeButtonEnabled(true);*/


        mDrawerToggle = new ActionBarDrawerToggle(
                this,                  /* host Activity */
                mDrawerLayout,         /* DrawerLayout object */
                R.drawable.ic_drawer,  /* nav drawer image to replace 'Up' caret */
                R.string.drawer_open,  /* "open drawer" description for accessibility */
                R.string.drawer_close  /* "close drawer" description for accessibility */
        ) {
            public void onDrawerClosed(View view) {

                invalidateOptionsMenu(); // creates call to onPrepareOptionsMenu()
            }

            public void onDrawerOpened(View drawerView) {

                invalidateOptionsMenu(); // creates call to onPrepareOptionsMenu()
            }
        };
        mDrawerLayout.setDrawerListener(mDrawerToggle);

public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
    selectItem(position);

}
//}

    private class DrawerItemClickListener implements ListView.OnItemClickListener {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        selectItem(position);

       System.out.println("&&&&&position"+position);

        switch(position){
            case 0:
                startActivity(new Intent(home.this, ChangeActivity.class));
              //  finish();

            case 1:

                startActivity(new Intent(home.this, home.class));
                //finish();

            case 2:

                startActivity(new Intent(home.this, info_values.class));
               // finish();

            default:
                break;


        }
    }

Answer 4

检查您的插入信息：

$sql = "INSERT INTO prescription (username,phone,procedure,address,emailid,reviews,followups,nextappointment)
                               VALUES('$username','$phone','$procedure','$address','$emailid','$reviews',$followups,'$nextappointment')";

注意：检查一下：https://www.w3schools.com/sql/sql_insert.asp

我的值未使用此命令插入数据库

4 个答案: