Question

这是从 mysql获取数据后的json结构蒙戈

        "_id" : ObjectId("595a1884ce238efb4d916231"),
        "" : [ 
            "\"DDO_CODE:8\"", 
            "\"DEPT_CODE:3\"", 
            "\"DDO_NAME:null\"", 
            "\"DDO_DESIGNATION:PRINCIPAL-IN-CHARGE, REGIONAL INSTITUTE OF PHARMACEUTICAL SCIENCE \\u0026 TECHNOLOGY (RIPSAT),\"", 
            "\"SELF_DRAW_TAG:O\"", 
            "\"DDO_ADDRESS:AGARTALA\"", 
            "\"CREATE_DATE:2002-11-30\"", 
            "\"CREATE_USER:SUPER\"", 
            "\"MODIFY_DATE:207-01-19\"", 
            "\"MODIFY_USER:SEEMA\"", 
            "\"SOURCE_CODE:11\"", 
            "\"DISTRICT_CODE:TW\"", 
            "\"SL_NO:8\"", 
            "\"PIN:1\""
        ]
    }


    **

但我希望mongo遵循以下风格。

**

    {
        "_id" : ObjectId("57ecd15b00296cadeb2de83c"),
        "DDO_CODE" : "3446",
        "DEPT_CODE" : "30",
        "DDO_NAME" : "DIVISIONAL FOREST OFFICER,",
        "DDO_DESIGNATION" : "DIVISIONAL FOREST OFFICER, TELIAMURA DIVISION",
        "SELF_DRAW_TAG" : "O",
        "DDO_ADDRESS" : "TELIAMURA, WEST TRIPURA",
        "CREATE_DATE" : "19-JUN-02",
        "CREATE_USER" : "MASTER",
        "MODIFY_DATE" : "19-JUN-02",
        "MODIFY_USER" : "MASTER",
        "SOURCE_CODE" : "404",
        "DISTRICT_CODE" : "TRW",
        "SL_NO" : "0",
        "PIN" : "2775"
    }

在我的json数据中，它只创建了2个字段（i字段是id，其他部分是第二次提交），但第二部分为每个提交了各种文件线。

    my code is... 
while (rsMembers.next()) {
                String toPrint = "";
                int count = 0;
                Gson gson = new Gson();
                for (int i = 1; i < rsMembers.getMetaData().getColumnCount() + 1; i++) {
                    toPrint += gson.toJson(rsMembers.getMetaData()
                            .getColumnName(i) + ":" + rsMembers.getObject(i)) + '\n';

                    queryResults.append(String.valueOf(" "
                            + rsMembers.getMetaData().getColumnName(i) + ":"
                            + rsMembers.getObject(i)));

                    count = rsMembers.getInt(1);

                }
                //System.out.println("DDDD  " + toPrint);
                System.out.println("Number of row:"+count);
                String[] output = toPrint.split("\n");
                System.out.println("PPP"+Arrays.toString(output));
                Map<String,Object> dataMap = new HashMap<String,Object>();
                //dataMap.put("", Arrays.toString(output));
                dataMap.put("", output);
                col.insert(new BasicDBObject(dataMap));

如何将sql数据转换为json＆amp;把它存放在mongo中

0 个答案: