如何使用postbackurl进行联属会员跟踪转换? 我在主要附属网络上发布的这样的回发网址
http://funto.xyz/ajax.php?uid=29&oid=45&offerid=4069&sub_id=#s2#
我正在尝试得到这样的回复,但没有回复请帮助如何跟踪转化
if(isset($_GET['uid']) && isset($_GET['oid']) && isset($_GET['offerid']) && isset($_GET['sub_id'])){
$uid = $_GET['uid'];
$oid = $_GET['oid'];
$offerid = $_GET['offerid'];
$s2 = $_GET['sub_id'];
//$uri_parts = explode('?', $_SERVER['REQUEST_URI'], 2);
//$myurl= 'http://' . $_SERVER['HTTP_HOST'] . $uri_parts[0].'?s1='.$sub_id.'&uid='.$uid.'&oid='.$oid;
$reffer = $_SERVER["HTTP_REFERER"];
$ip = $_SERVER['REMOTE_ADDR'];
$subid = time();
setcookie($s2, $s2, time() + (86400 * 30), "/");
$details = json_decode(file_get_contents("http://ipinfo.io/{$ip}/json"));
$ip = $details->ip;
$country = $details->country;
$datetime = date('Y-m-d H:i:s');
$date = date('Y-m-d');
$query="INSERT INTO clicks (uid,oid,offerid,subid,clicks,signup,reffer_link,ip,country,proxy, date,datetime) VALUES ('$uid','$oid','$offerid','$subid','1','$s2','$reffer','$ip','$country','proxy', '$date','$datetime')";
$result = mysqli_query($con,$query) or die("Error: ".mysqli_error($con));
if ($result == 1){
$qry = "select offername from offers where oid = '$oid'";
$run = mysqli_query($con, $qry) or die(mysqli_error($con));
$res = mysqli_fetch_array($run);
$link = $res['offername'].$subid;
//$myurl= 'http://' . $_SERVER['HTTP_HOST'] . $uri_parts[0].'?s1='.$sub_id
//header ("Loca`enter code here`tion: $myurl");
header ("Location: $link");
}
}