我有这个代码..它将显示当年和第一个月和第二个月的第一天的月份列表
$cur_year = date("Y");
$next_year = $cur_year+1;
for($m=1; $m<=12; ++$m)
{
$monthName=date('F', mktime(0, 0, 0, $m, 1)).'';
$monthNumber=date('m', mktime(0, 0, 0, $m, 1)).'';
$nextmonth=$monthNumber+1;
echo "$monthName<br />";
echo "$cur_year-$monthNumber-01<br />";
echo "$cur_year-$nextmonth-01<br /><br />";
}
我希望像这样显示
January
2017-01-01
2017-02-01
February
2017-02-01
2017-03-01
up to December
December
2017-12-01
2018-01-01
当前的输出
January
2017-01-01
2017-2-01
February
2017-02-01
2017-3-01
up to December
December
2017-12-01
2017-13-01
答案 0 :(得分:2)
在PHP中使用date()
函数
<?php
$cur_year = date('Y');
$next_year = $cur_year + 1;
for ($m = 1; $m <= 12; ++$m)
{
$monthName = date('F', mktime(0, 0, 0, $m, 1));
$currentMonthText = date('Y-m-d', mktime(0, 0, 0, $m, 1));
$nextMonthText = date('Y-m-d', mktime(0, 0, 0, $m + 1, 1));
echo $monthName, '<br />', PHP_EOL;
echo $currentMonthText, '<br />' . PHP_EOL;
echo $nextMonthText, '<br />' . PHP_EOL;
}
答案 1 :(得分:0)
您可以使用&#34; sprintf()&#34;。
您编辑一行。
echo "$cur_year-".sprintf("%02d",$nextmonth)."-01<br /><br />";
答案 2 :(得分:0)
试试这段代码:
<img class="adjust" src="https://unsplash.it/3000/3000">