Question

我从包含JSON数组的API得到以下响应，我试图删除除title，column和searchSourceJSON之外的所有元素：

"hits": [
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Integration-Enabled",
        "_score": 1,
        "_source": {
            "title": "demo Media Integration - Enabled",
            "description": "",
            "hits": 0,
            "columns": [
                "_source"
            ],
            "sort": [
                "timestamp",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"value\":\"Media Integration\",\"disabled\":false},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Integration\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Action\",\"value\":\"Enable\",\"disabled\":false},\"query\":{\"match\":{\"Action\":{\"query\":\"Enable\",\"type\":\"phrase\"}}}}],\"query\":{\"query_string\":{\"query\":\"*\",\"analyze_wildcard\":true}}}"
            }
        }
    },
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Import-True",
        "_score": 1,
        "_source": {
            "title": "demo Media Import - True",
            "description": "",
            "hits": 0,
            "columns": [
                "FormFactor",
                "_type",
                "Identity"
            ],
            "sort": [
                "_type",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"query\":{\"query_string\":{\"analyze_wildcard\":true,\"query\":\"*\"}},\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"disabled\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"negate\":false,\"value\":\"Media Import\"},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Import\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Successful\",\"value\":\"True\",\"disabled\":false},\"query\":{\"match\":{\"Successful\":{\"query\":\"True\",\"type\":\"phrase\"}}}}]}"
            }
        }
    }
]

有人可以帮我弄清楚如何使用JavaScript从这个JSON文档中删除不需要的元素吗？

编辑：回答，谢谢大家的好消息！

Answer 1

一种省力的方法是使用Array#Map，然后只选择你想要的元素。

＆＃13;

var hits = [
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Integration-Enabled",
        "_score": 1,
        "_source": {
            "title": "demo Media Integration - Enabled",
            "description": "",
            "hits": 0,
            "columns": [
                "_source"
            ],
            "sort": [
                "timestamp",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"value\":\"Media Integration\",\"disabled\":false},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Integration\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Action\",\"value\":\"Enable\",\"disabled\":false},\"query\":{\"match\":{\"Action\":{\"query\":\"Enable\",\"type\":\"phrase\"}}}}],\"query\":{\"query_string\":{\"query\":\"*\",\"analyze_wildcard\":true}}}"
            }
        }
    },
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Import-True",
        "_score": 1,
        "_source": {
            "title": "demo Media Import - True",
            "description": "",
            "hits": 0,
            "columns": [
                "FormFactor",
                "_type",
                "Identity"
            ],
            "sort": [
                "_type",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"query\":{\"query_string\":{\"analyze_wildcard\":true,\"query\":\"*\"}},\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"disabled\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"negate\":false,\"value\":\"Media Import\"},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Import\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Successful\",\"value\":\"True\",\"disabled\":false},\"query\":{\"match\":{\"Successful\":{\"query\":\"True\",\"type\":\"phrase\"}}}}]}"
            }
        }
    }
]

var filtered = hits.map(function(hit){
  return { title : hit._source.title, searchSourceJSON : hit._source.exampleSavedObjectMeta.searchSourceJSON, columns : hit._source.columns}
})

console.log(filtered)

＆＃13;

Answer 2

你可以：

使用map方法横切所有结果（这往往代价很高）。
或者因为它似乎是要求Elastic Search过滤掉ES发送的响应。因此，网络流量减少，您可以避免清理数据。

您可以这样添加filter path on your query string：

x[,c("Alley", "Fence")] <- lapply(x[,c("Alley", "Fence")], function(x){`levels<-`(addNA(x), c(levels(x), "None"))})

Answer 3

您可以解析JSON，然后映射以创建一个包含仅具有所需属性的对象的新数组：

const data = JSON.parse(yourJSON);
const hits = data.hits.map(hit => ({
    title: hit._source.title,
    searchSourceJSON: hit._source.exampleSavedObjectMeta.searchSourceJSON
});

Answer 4

var result=(function(){//IIFE to enshure garbage collection
  var hits=[...];//your data
  return hits.map(hit=>{hit["_source"].title,hit["_source"].colums,hit.exampleSavedObjectMeta.searchSourceJSON});
});

这将删除所需的所有属性（垃圾收集它们）。

Answer 5

试试这个：

＆＃13;

var jsonObj = [
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Integration-Enabled",
        "_score": 1,
        "_source": {
            "title": "demo Media Integration - Enabled",
            "description": "",
            "hits": 0,
            "columns": [
                "_source"
            ],
            "sort": [
                "timestamp",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"value\":\"Media Integration\",\"disabled\":false},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Integration\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Action\",\"value\":\"Enable\",\"disabled\":false},\"query\":{\"match\":{\"Action\":{\"query\":\"Enable\",\"type\":\"phrase\"}}}}],\"query\":{\"query_string\":{\"query\":\"*\",\"analyze_wildcard\":true}}}"
            }
        }
    },
    {
        "_index": ".example_demo",
        "_type": "search",
        "_id": "demo-Media-Import-True",
        "_score": 1,
        "_source": {
            "title": "demo Media Import - True",
            "description": "",
            "hits": 0,
            "columns": [
                "FormFactor",
                "_type",
                "Identity"
            ],
            "sort": [
                "_type",
                "asc"
            ],
            "version": 1,
            "exampleSavedObjectMeta": {
                "searchSourceJSON": "{\"index\":\"[demo-]YYYY.MM\",\"query\":{\"query_string\":{\"analyze_wildcard\":true,\"query\":\"*\"}},\"highlight\":{\"pre_tags\":[\"@example-highlighted-field@\"],\"post_tags\":[\"@/example-highlighted-field@\"],\"fields\":{\"*\":{}},\"fragment_size\":2147483647},\"filter\":[{\"meta\":{\"disabled\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"_type\",\"negate\":false,\"value\":\"Media Import\"},\"query\":{\"match\":{\"_type\":{\"query\":\"Media Import\",\"type\":\"phrase\"}}}},{\"meta\":{\"negate\":false,\"index\":\"[demo-]YYYY.MM\",\"key\":\"Successful\",\"value\":\"True\",\"disabled\":false},\"query\":{\"match\":{\"Successful\":{\"query\":\"True\",\"type\":\"phrase\"}}}}]}"
            }
        }
    }
];

var res = jsonObj.map(function(item) {
  return { 
           "title": item._source.title, 
           "columns": item._source.columns,
           "searchSourceJSON": item._source.exampleSavedObjectMeta.searchSourceJSON
         };
});

console.log(res);

＆＃13;

如何从此JSON数组中删除不需要的元素？

5 个答案: