python和RS中的RSA加密解密JS

时间：2017-07-03 19:44:26

标签： python encryption rsa pycrypto jsencrypt

我是密码学的全新人物。我想从服务器端生成RSA密钥对，并将其发送给所有客户端（浏览器）。但在此之前，我只是通过加密python中的数据并通过pubnub发送到index.html文件并尝试在JavaScript中解密来测试场景。问题是当我通过加密进行加密时

random_generator = Random.new().read
key = RSA.generate(1024, random_generator)
print key.exportKey() #<--private key
public_key = key.publickey()
print public_key.exportKey() #<--public key
msg = "hello"
enc_data = public_key.encrypt(msg, 32)
print '----ENCRYPTED DATA----'
enc = enc_data[0]

并发送加密数据enc，它给了我这个错误：

UnicodeDecodeError: 'utf8' codec can't decode byte 0xc4 in position 2: invalid continuation byte

我尝试将其转换为

enc = base64.b64encode(enc_data[0])

并且发送时没有错误。但JS解密方法获得无

  var enc_from_python = $('#input').val();
  console.log("ENCRYPTED data:", enc_from_python);
  var decrypt = new JSEncrypt();
  decrypt.setPrivateKey($('#privkey').val());
  var uncrypted = decrypt.decrypt(enc_from_python);
  console.log(">>>",uncrypted);  //<-- this is None ! why ?

这两个代码都可以自己进行加/减。我还尝试使用python中收到的密钥对来加密/解析JS中的数据，这很有效。我想问题是来自Pycrypto的编码数据的unicode编码格式不匹配。任何人都可以告诉我在这里我错过了什么。

Python的完整代码：

import time
from pubnub.pnconfiguration import PNConfiguration
from pubnub.pubnub import PubNub

from Crypto.PublicKey import RSA
from Crypto import Random
import base64

pnconfig = PNConfiguration()
pnconfig.subscribe_key = 'demo'
pnconfig.publish_key = 'demo'
channel = "my_channel" 
pubnub = PubNub(pnconfig)

def my_publish_callback(envelope, status):
    if not status.is_error():
        pass  # Message successfully published to specified channel.
    else:
        pass  # Handle message publish error. Check 'category' property to find out possible issue


time.sleep(1)
random_generator = Random.new().read
key = RSA.generate(1024, random_generator)
print key.exportKey() #<--private key
public_key = key.publickey()
print public_key.exportKey() #<--public key
msg = "hello"
enc_data = public_key.encrypt(msg, 32)
print '----ENCRYPTED DATA----'
#enc = enc_data[0]
enc = base64.b64encode(enc_data[0])

print enc        
#print type(enc_data[0])
print '----ENCRYPTED DATA----'
print  ''
print '----DECRYPTED DATA begin----'
print key.decrypt(enc_data[0])
print '----DECRYPTED DATA end----'      

pubnub.publish().channel(channel).message({"data": enc , "private": (key.exportKey()), "public" : (public_key.exportKey())}).async(my_publish_callback)

和完整的JS代码是; 

<!doctype html>
<html>
  <head>
    <title>JavaScript RSA Encryption</title>
    <script src="http://code.jquery.com/jquery-1.8.3.min.js"></script>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/jsencrypt/2.3.1/jsencrypt.min.js"></script>
    <script src="https://cdn.pubnub.com/sdk/javascript/pubnub.4.12.0.min.js"></script>
    <script type="text/javascript">

      // Call this code when the page is done loading.
      $(function() {
        pubnub = new PubNub({
          publish_key: 'demo',
          subscribe_key: 'demo'
        });  

        pubnub.subscribe({
            channels: ['my_channel']
        }); 

    pubnub.addListener({
        message: function(message) {
            var msg = message.message;
            console.log("msg:" + JSON.stringify(msg));

             if (msg.private){
                $("#privkey").val(msg.private);
             }

             if(msg.public){
                $("#pubkey").val(msg.public);
             }

             if(msg.data){
                $("#input").val(msg.data);
             }           
        }    
    })      

        // Run a quick encryption/decryption when they click.
        $('#testme').click(function() {
          var enc_from_python = $('#input').val();
          console.log("ENCRYPTED data:", enc_from_python);
          // Decrypt with the private key...
          var decrypt = new JSEncrypt();
          decrypt.setPrivateKey($('#privkey').val());
          var uncrypted = decrypt.decrypt(enc_from_python);
          console.log(">>>",uncrypted);  //<-- this is None ! why ?
          // Now a simple check to see if the round-trip worked.
          if (uncrypted == $('#input').val()) {
            alert('It works!!!');
          }
          else {
            alert('Something went wrong....');
          }
        });
      });
    </script>
  </head>
  <body>
    <label for="privkey">Private Key</label><br/>
    <textarea id="privkey" rows="15" cols="65">   </textarea><br/>
    <label for="pubkey">Public Key</label><br/>
    <textarea id="pubkey" rows="15" cols="65">    </textarea><br/>
    <label for="input">Text to decrypt:</label><br/>
    <textarea id="input" name="input" type="text" rows=4 cols=70>This is a test!</textarea><br/>
    <input id="testme" type="button" value="Decrypt Me!!!" /><br/>
  </body>
</html>

1 个答案:

答案 0 :(得分：7)

如果您使用public class Generator { public static void main(String[] args) { Scanner scan = new Scanner(System.in); /* Prints 10 random numbers Random num = new Random(); int number; for(int counter=1; counter<=1;counter++){ number = num.nextInt(10); System.out.println(number); } */ Random num1 = new Random(); Random num2 = new Random(); Random num3 = new Random();; int number1; int number2; int number3; number1 = num1.nextInt(10) + 2; number2 = num2.nextInt(10) * 2; number3 = -num3.nextInt(10) * 2; System.out.println("Solve the quadratic: "+number1 + "x"+"\u00B2+" + number2 + "x" + number3); double answer = -number2/2/number1+Math.pow(Math.pow(number2,2)-4*number1*number3,0.5)/2/number1; double answer2 = -number2/2/number1-Math.pow(Math.pow(number2,2)-4*number1*number3,0.5)/2/number1; DecimalFormat df = new DecimalFormat("#.####"); df.setRoundingMode(RoundingMode.CEILING); for (Number n : Arrays.asList(answer, answer2)) { Double d = n.doubleValue(); System.out.println(df.format(d)); } //System.out.println(answer); <---- works if answer is not rounded. System.out.println("Enter answer:"); double x = scan.nextDouble(); if(x == answer){ System.out.println("Correct"); }else{ System.out.println("Try again"); System.out.println("Enter answer:"); double x1 = scan.nextDouble(); if(x1 == answer){ System.out.println("Correct"); }else{ System.out.println("Try again"); } } } } 则可以。

这是python代码。

我只测试了python 3，但我相信它在python 2中应该与Crypto.Cipher.PKCS1_v1_5导入一样。

__future__

从明文“hello stackoverflow！”输出样本密文：

from __future__ import unicode_literals, print_function  # python2
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_v1_5
import base64

private_key = """-----BEGIN RSA PRIVATE KEY-----
MIIBOwIBAAJBANBOMQo9wX55+w1ijEaPoYRP2T4BOjoFv3ma0QWqYYQ8FH0z14Zc
B/jb0j2PWpyNcsUUBovj+yWxQnQohCck64kCAwEAAQJBAL4s9PbNpO9MfFkfBMSS
8zoyEDtcsYUxpDtojbandDpdXfvn5D279QaOVLb1C3DgQTTEmroYB8dbeZBc5YJC
2AECIQDqyUn68ehRcx/EyLMUB1IuckZBWCIApgfn7phgVwSwiQIhAOMgY4bN+xrx
UV15Ian4ZbkME1IbAvDPcWuNGHxdsaMBAiBoz0K/S44yDfp4lj+bCUmeglTqhrVn
JLcSymgrWa02QQIhAMJFvPvcilGkYl1atCHHt3LN0mTjd+N0/OXq3SvblIsBAiAc
8RzaV1GmjMEJxw9vM/tQwQg0kyAPlITMRXnwGA6E0A==
-----END RSA PRIVATE KEY-----"""

rsa = RSA.importKey(private_key)
cipher = PKCS1_v1_5.new(rsa)

def encrypt(msg):
    ciphertext = cipher.encrypt(msg.encode('utf8'))
    return base64.b64encode(ciphertext).decode('ascii')

def decrypt(msg):
    ciphertext = base64.b64decode(msg.encode('ascii'))
    plaintext = cipher.decrypt(ciphertext, b'DECRYPTION FAILED')
    return plaintext.decode('utf8')

ciphertext = encrypt('hello stackoverflow!')
print(ciphertext)
plaintext = decrypt(ciphertext)
print(plaintext)

在javascript中，原始代码应该有效。这是一个简化版本，用于演示此特定密文和私有rsa密钥的工作原理。

tZDRXXcf7ppbVr9JBHQ3+2k3geofl8BdDmLT3HRoqBGvfknY+xISbvy5hYH2alPAUDu2ae4iSYsLyRFBOnzpgw==

const decrypt = () => {
  const privateKey = document.getElementById('private_key').value
  const cipherText = document.getElementById('ciphertext').value
  const decrypt = new JSEncrypt()
  decrypt.setPrivateKey(privateKey)
  const plainText = decrypt.decrypt(cipherText) || 'DECRYPTION FAILED'
  document.getElementById('plaintext').innerHTML = plainText
}
document.querySelector('button').addEventListener('click', decrypt)

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