考虑以下伪代码来证明我的问题:
import pytest
@pytest.fixture
def param1():
# return smth
yield "wilma"
@pytest.fixture
def param2():
# return smth
yield "fred"
@pytest.fixture
def bar(param1, param2):
#do smth
return [Bar(param1, param2), Bar(param1, param2)]
@pytest.fixture
def first_bar(bar):
return bar[0]
class Test_first_bar:
# FIXME: how do I do that?
#def setup_smth???(self, first_bar):
# self.bar = first_bar
def test_first_bar_has_wilma(self):
# some meaningful check number 1
assert self.bar.wilma == "wilma"
def test_first_bar_some_other_check(self):
# some meaningful check number 2
assert self.bar.fred == "fred"
基本上我想将first_bar
fixture传递给我的Test_first_bar
类,以便在其所有测试方法中重用该对象。我该如何处理这种情况?
Python 3,如果重要的话。
答案 0 :(得分:2)
在这里,您可以将灯具定义为autouse
。这将为您班级的所有测试自动调用。在这里,我无法理解[Bar(param1, param2), Bar(param1, param2)]
是什么。嗯,这不是重点,如果其余的代码工作正常,你可以尝试下面的解决方案。我已经用静态变量替换了代码,以验证它是否正常工作,并且它在我的最终工作正常。
import pytest
@pytest.fixture
def param1():
# return smth
yield "wilma"
@pytest.fixture
def param2():
# return smth
yield "fred"
@pytest.fixture
def bar(param1, param2):
# do smth
return [Bar(param1, param2), Bar(param1, param2)]
@pytest.fixture(scope='function', autouse=True)
def first_bar(bar, request):
request.instance.bar = bar[0]
class Test_first_bar:
def test_first_bar_has_wilma(self,request):
print request.instance.bar
def test_first_bar_some_other_check(self,request):
print request.instance.bar
如果您不想将夹具设为autouse
,那么您可以在测试之前调用它。像,
import pytest
@pytest.fixture
def param1():
# return smth
yield "wilma"
@pytest.fixture
def param2():
# return smth
yield "fred"
@pytest.fixture
def bar(param1, param2):
# do smth
return [Bar(param1, param2), Bar(param1, param2)]
@pytest.fixture(scope='function')
def first_bar(bar, request):
request.instance.bar = bar[0]
class Test_first_bar:
@pytest.mark.usefixtures("first_bar")
def test_first_bar_has_wilma(self,request):
print request.instance.bar
@pytest.mark.usefixtures("first_bar")
def test_first_bar_some_other_check(self,request):
print request.instance.bar