Question

我正在创建一个Spring Boot应用程序，我想通过rest api创建一个交换：

    RestTemplate restTemplate = new RestTemplate();

    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_JSON);

    String auth = "guest:guest";
    byte[] encodedAuth = Base64.encodeBase64(auth.getBytes(Charset.forName("US-ASCII")) );
    String authHeader = "Basic " + new String( encodedAuth );
    headers.set( "Authorization", authHeader );

    String uri = "http://localhost:15672/api/exchanges/%2f/my-new-exchange-new";

    String input = "{\"type\":\"direct\",\"durable\":\"true\"}";

    HttpEntity<String> entity = new HttpEntity<String>(input,headers);

    ResponseEntity<String> response = restTemplate.exchange(uri, HttpMethod.PUT, entity, String.class);

    System.out.println(response);

但是我总是得到错误：

PUT request for "http://localhost:15672/api/exchanges/%252f/my-new-exchange-new" resulted in 404 (Not Found); invoking error handler

你可以帮我一个提示吗？谢谢！

如果您需要，可以尝试一下：https://github.com/pkid/rabbittest

Answer 1

问题很可能是错误中返回的ParseObject.pinAllInBackground(objects); chart.xScale(d3.time.scale())应用于uri变量的网址编码。为避免这种情况，您需要使用与RestTemplate一起使用的%252f方法，并告诉它假设网址已经编码：

RestTemplate

RabbitMQ Rest API创建Exchange失败

1 个答案: