Question

我有一个xpage，其中字段是动态创建的。默认情况下，有3个，但您可以单击一个按钮添加任意多个，命名约定＆＃34; ObjectiveDetails1＆＃34;，＆＃34; ObjectiveDetails2＆＃34;等等。

我正在尝试处理空白字段...例如，字段1和2中有内容，3和4中没有内容，但是5中的内容。我想要做的是将内容从字段5转移到第一个可用空白，在这种情况下为3.同样，如果字段1,2,4,5中有内容，则需要4中的内容，进入字段3，然后进入5中的内容进入字段4等。那一刻，我只设法将内容向上移动。

因此，如果字段2,3,4为空白但5具有内容，则仅将内容移动到4，其中 - 我需要将其移动到字段2中。

我希望我已经足够好解释了......目前的代码有点乱......

for (var i = 1; i < viewScope.rows+1; i++) {
print("Starting Array.....");
if(applicationScope.get("BreakAllCode")==true){
  break;
}
var objFieldName:string = "ObjectiveDetails" +i;
print ("Field Name: " + objFieldName);

var fieldValue = document1.getItemValueString(objFieldName);

print ("Field Value: " + fieldValue);
if (fieldValue =="" || fieldValue==null){
    print("EMPTY"); 

    // We now need to delete the 3 fields related to this objective
    var updFieldName:string = "ObjectiveUpdates" +i;
    var SAFieldName:string = "ObjectiveSelfAssessment" +i;

    // Before we delete the fields, we need to check if the next field is blank
    // and if not, copy its contents into this field.

    for (var n =i+1; n < viewScope.rows+1; n++) {
    if(applicationScope.get("BreakAllCode")==true){
     break;
    }

        if(document1.hasItem("ObjectiveDetails" +n)){       
            print("Next field: " +"ObjectiveDetails" +n);
            var nextFieldValue = document1.getItemValueString("ObjectiveDetails" +n);

            if (!nextFieldValue =="" || !nextFieldValue==null){
                // Now copy the content into the field
                var nextFieldName:string = "ObjectiveDetails" +n;
                var previousNo = n-1;
                var previousFieldName:string = "ObjectiveDetails" +previousNo;
                print ("Previous field: " + previousFieldName);
                document1.replaceItemValue(previousFieldName,nextFieldValue);

                // Now clear the content from next field
                document1.replaceItemValue(nextFieldName,"");
            }else{
                // Do nothing
            }
        }else{
            print("Last field");
        }
    }
    // Remove items from the document
    //document1.removeItem(objFieldName);
    //document1.removeItem(updFieldName);
    //document1.removeItem(SAFieldName);

    // Remove fields from our arrays
    //viewScope.fields.splice(i-1, 1);
    //viewScope.fields2.splice(i-1, 1);
    //viewScope.fields3.splice(i-1, 1);

    // Update the row variable
    //viewScope.rows--;
    //document1.replaceItemValue("rows",viewScope.rows);
    //document1.save();

    // We now need to "re-index" the array so that the fields are numbered corectly

}else{
    print("We have a value");
}
}

使用beforePageLoad更新：

viewScope.rows = document1.getItemValueInteger("rows");

var rowCount:integer = viewScope.rows;
var newCount:integer = 0;

while(newCount<rowCount){
if (!viewScope.fields) {
    viewScope.fields = [];
    viewScope.fields2 = [];
    viewScope.fields3 = [];
}

viewScope.fields.push("ObjectiveDetails" + (viewScope.fields.length + 1));
viewScope.fields2.push("ObjectiveUpdates" +  (viewScope.fields2.length + 1));
viewScope.fields3.push("ObjectiveSelfAssessment" +  (viewScope.fields3.length + 1));

newCount++;
}

Answer 1

如果我理解你的问题，那么这段代码应该有效（未经测试）：

(depth, d1, d2, .., dn)

Answer 2

这应该是你的核心算法：

var writeIndex = 0;
for (var readIndex = 1; readIndex <= viewScope.rows; readIndex++) {
    var value = document1.getItemValueString("ObjectiveDetails" + readIndex);
    if (value) {
        writeIndex++;
        if (readIndex !== writeIndex) {
            document1.removeItem("ObjectiveDetails" + readIndex);
            document1.replaceItemValue("ObjectiveDetails" + writeIndex, value);
        }
    } else {
        document1.removeItem("ObjectiveDetails" + readIndex);
    }
}
viewScope.rows = writeIndex;

代码

删除所有空字段
将字段重命名为ObjectiveDetails1，ObjectiveDetails2，ObjectiveDetails3，...和
将生成的行数写回viewScope变量＆＃34; rows＆＃34;。

动态移动内容

2 个答案: