Question

我正在解析json以显示tableview中的内容。我有包含解析的json的数组在getReceivedData中填充，在UITAbleView Delegate方法之后调用。所以在填充tableview时遇到问题，因为当编译器尝试填充它时，数组尚未初始化。

- (void)getReceivedData:(NSMutableData *)data sender:(RestAPI *)sender{

NSError * error=nil;
NSArray *receivedData = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
NSString *dictionaryKey=@"department";
NSString *predicateString=@"software";
NSPredicate *predicate=[NSPredicate predicateWithFormat:@" %K == %@ ", dictionaryKey,predicateString];
NSArray *shortlisted=[receivedData filteredArrayUsingPredicate:predicate];
for(int i = 0; i<shortlisted.count; i++)
{
    NSDictionary *detailItems=[shortlisted objectAtIndex:i];
    NSString *name=[detailItems objectForKey:@"emp_name"];
    NSString *designation=[detailItems objectForKey:@"designation"];
    NSString *email=[detailItems objectForKey:@"email"];
    NSString *phone_no=[detailItems objectForKey:@"phone_no"];
  //  NSString *image=[detailItems objectForKey:@"url_path"];
    dictionary1=[NSMutableDictionary dictionaryWithObjectsAndKeys:
               name, @"keyname",
                designation, @"keydesignation",
                email, @"keyid",
                phone_no, @"keyphone",

               nil];
     [myObject1 addObject:dictionary1];
   }

 }

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:
(NSInteger)section{
   if(isfiltered==YES){
       return [filteredArray count];
  }
   else{
  return [myObject1 count];
   }

 }
-(UITableViewCell *)tableView:(UITableView *)tableView 
cellForRowAtIndexPath:(NSIndexPath *)indexPath{

MyTableCell *cell=[tableView dequeueReusableCellWithIdentifier:@"myCell"];
if(!cell){
    [tableView registerNib:[UINib nibWithNibName:@"MyTableCell" bundle:nil] 
forCellReuseIdentifier:@"myCell"];
    cell=[tableView dequeueReusableCellWithIdentifier:@"myCell"];
}


if(isfiltered==NO)
{
  NSDictionary * tmpdict= [myObject objectAtIndex:indexPath.row];
    cell.nameLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyname"]];
    cell.designationLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keydesignation"]];
    cell.idLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyid"]];
    cell.phoneLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyphone"]];
    cell.mainImg.image = [UIImage imageNamed:[tmpdict objectForKeyedSubscript:@"keyimage"]];

}
else{
    NSDictionary * tmpdict= [filteredArray objectAtIndex:indexPath.row];
    cell.nameLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyname"]];
    cell.designationLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keydesignation"]];
    cell.idLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyid"]];
    cell.phoneLabel.text=[NSMutableString stringWithFormat:@"%@",[tmpdict objectForKeyedSubscript:@"keyphone"]];
             cell.mainImg.image = [UIImage imageNamed:[tmpdict objectForKeyedSubscript:@"keyimage"]];
      }
   return cell;


}

该窗口应该可以查看表格

Answer 1

首先，在一个可变字典中，你必须给对象然后它的键。你做错了

for(int i = 0; i<shortlisted.count; i++)
{
    NSDictionary *detailItems=[shortlisted objectAtIndex:i];
    NSString *name=[detailItems objectForKey:@"emp_name"];
    NSString *designation=[detailItems objectForKey:@"designation"];
    NSString *email=[detailItems objectForKey:@"email"];
    NSString *phone_no=[detailItems objectForKey:@"phone_no"];


dictionary1=[NSMutableDictionary dictionaryWithObjectsAndKeys:
                name,@"keyname",
                designation,@"keydesignation",
                email,@"keyid",
                phone_no,@"keyphone",
               nil];
 [myObject1 addObject:dictionary1];
}

Answer 2

实际上这并不是像你一样初始化字典的正确方法，@“％@”使用％@是任何对象的格式字符串中的占位符。

dictionary1=[NSMutableDictionary dictionaryWithObjectsAndKeys:
                name,@"keyname",
                designation,@"keydesignation",
                email,@"keyid",
                phone_no,@"keyphone",
               nil];

ios中的程序流问题

2 个答案: