我想要具有最大ID的行。我需要id为2的行。
我的表格
请使用以下脚本创建表格。
/****** Object: Table [dbo].[Customers] Script Date: 03/07/2017 14:48:14 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Customers](
[CustomerID] [bigint] IDENTITY(1,1) NOT NULL,
[Name] [nchar](10) NULL,
CONSTRAINT [PK_Customers] PRIMARY KEY CLUSTERED
(
[CustomerID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
/****** Object: Table [dbo].[Instalments] Script Date: 03/07/2017 14:48:14 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Instalments](
[id] [int] IDENTITY(1,1) NOT NULL,
[Amount] [int] NULL,
[Date] [date] NULL,
[CustomerID] [bigint] NULL,
CONSTRAINT [PK_Test] PRIMARY KEY CLUSTERED
(
[id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
SET IDENTITY_INSERT [dbo].[Customers] ON
INSERT [dbo].[Customers] ([CustomerID], [Name]) VALUES (1, N'Muddassir ')
INSERT [dbo].[Customers] ([CustomerID], [Name]) VALUES (2, N'Irshad ')
SET IDENTITY_INSERT [dbo].[Customers] OFF
SET IDENTITY_INSERT [dbo].[Instalments] ON
INSERT [dbo].[Instalments] ([id], [Amount], [Date], [CustomerID]) VALUES (1, 500, CAST(N'2014-09-30' AS Date), 1)
INSERT [dbo].[Instalments] ([id], [Amount], [Date], [CustomerID]) VALUES (2, 600, CAST(N'2015-09-30' AS Date), 1)
INSERT [dbo].[Instalments] ([id], [Amount], [Date], [CustomerID]) VALUES (3, 800, CAST(N'2014-09-30' AS Date), 2)
SET IDENTITY_INSERT [dbo].[Instalments] OFF
我的查询
这是我正在使用的查询。
SELECT a.CustomerID,a.[Name],b.Amount,b.Date,b.id from Customers as a
left join Instalments as b On b.CustomerID=a.CustomerID
我的结果 这是我查询的结果。
CustomerID Name Amount Date id
1 Muddassir 500 2014-09-30 1
1 Muddassir 600 2015-09-30 2
2 Irshad 800 2014-09-30 3
我想要什么结果? 但我想要低于结果。我想要所有只有最大ID的行
CustomerID Name Amount Date id
1 Muddassir 600 2015-09-30 2
2 Irshad 800 2014-09-30 3
答案 0 :(得分:3)
试试这个
SELECT CustomerID
,[Name]
,Amount
,[Date]
,id
FROM (
SELECT a.CustomerID
,a.[Name]
,b.Amount
,b.DATE
,b.id
,Row_NUmber() OVER (
PARTITION BY a.CustomerID ORDER BY b.DATE DESC
) AS Rno
FROM Customers AS a
LEFT JOIN Instalments AS b ON b.CustomerID = a.CustomerID
) DT
WHERE DT.Rno = 1
结果
CustomerID Name Amount Date id
1 Muddassir 600 2015-09-30 2
2 Irshad 800 2014-09-30 3
答案 1 :(得分:1)
您可以使用MAX()
获取子查询中的最高ID,并将其与当前ID Instalments
进行比较。
试试这个:
SELECT a.CustomerID,a.[Name],b.Amount,b.Date,b.id FROM Customers AS a
LEFT JOIN Instalments AS b ON b.CustomerID=a.CustomerID
WHERE b.id = (SELECT MAX(id) FROM Instalments AS i WHERE i.CustomerID = a.CustomerID);
答案 2 :(得分:1)
您确定不需要始终为每位客户提供最新的分期付款吗?
这将是:
SELECT a.CustomerID
,a.Name
,b.Amount
,b.Date
,b.id
FROM Customers AS a
LEFT JOIN Instalments AS b
ON b.CustomerID=a.CustomerID
AND b.Date = (SELECT MAX(Date)
FROM Instalments T
WHERE T.CustomerID = b.CustomerID
)