Question

如何在批处理文件中复制没有开始编号字符的文件

例如我的Dir列出了它：

12red.pcx
9red.pcx
96blue.pcx
alipro.pcx

然后我只需要批量复制alipro.pcx

将此批处理代码用于以数字char开头的复制文件：

@echo off
set Design_path=D:\
set USB_path=E:\usb\
set t12=12*.pcx
set t9=9*.pcx
set t6=6*.pcx
set tsize=*.pcx
set design12=Dis_12
set design9=Dis_9
set design6=Dis_6
set designsize=D_Size
rem // Create Dir if not exist
if not exist %Design_path%%design12% (mkdir %Design_path%%design12%) 
if not exist %Design_path%%design9% (mkdir %Design_path%%design9%) 
if not exist %Design_path%%design6% (mkdir %Design_path%%design6%) 
if not exist %Design_path%%designsize% (mkdir %Design_path%%designsize%) 
if exist %USB_path%%t12% copy %USB_path%%t12% %Design_path%%design12%
if exist %USB_path%%t9% copy %USB_path%%t9% %Design_path%%design9%
if exist %USB_path%%t6% copy %USB_path%%t6% %Design_path%%design6%

Answer 1

此解决方案使用findstr的有限RegEx功能来仅选择行开头的（^锚点在开头），带有否定的字符类[^]，但不是零到九[^0-9]

for /f "delims=" %%a in (
  'dir /B *.pcx^|findstr "^[^0-9]" '
) Do Echo copy %%a x:\whereever

如果要排除特殊号码，可以使用不同的RegEx 过滤与<{1}}选项匹配的行您可以使用SPACE分隔多个RegEx

/V

示例输出

for /f "delims=" %%a in (
  'dir /B "*.pcx" ^|findstr /V "^6 ^9 ^12" '
) Do (
  Echo %%a
  Rem copy ...
)

Answer 2

现在用于复制任何没有开始的文件，编号为9,6,12

例如我的列表：

3366.pcx
12gun.pcx
9ghost2.pcx
6bgre.pcx
avf.pcx

我只需要复制avf.pcx和3366.pcx。

这是我的代码

for /f "delims=" %%a in ('dir %USB_path% /b *.pcx^|findstr /r /c:"^[^9][^6][^12]" ') do (
    echo %%a
    copy "%USB_path%%%a" "%Design_path%%designsize%"
  )

复制文件不要以批处理中的数字字符开头

2 个答案: