经过数小时的网络搜索并试图理解文档后,我似乎无法找到解决此问题的方法。
我有一个使用ASyncTask连接到服务器的应用程序我有3个地址到" test"连接。
现在问题是当我使用Myconnection.connect()时,如果没有已知地址或死链接,后台任务就会挂起。
如果使用死链接或死机服务器挂起并且没有收到任何响应,我该如何测试此连接
Logcat中的错误是
package nodomain.myapplication;
import android.os.AsyncTask;
import android.util.Log;
import org.w3c.dom.Text;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.UnsupportedEncodingException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLEncoder;
/**
* Created by Shab on 02/07/2017.
*/
public class bgWorker extends AsyncTask<Void, Integer, Void> {
@Override
protected Void doInBackground(Void... params)
{
String db_Username = "root";
String db_Password = "";
String db_Name = "testdb";
String url1 = "http://10.0.0.2/testdb/connection.php"; //DEAD? (NO RESPONSE)
(Program Hang until exception is called)
String url2 = "http://www.google.com"; //OK RESPONSE 200
String url3 = "http://localhost/myPage.php"; //NO RESPONSE
try {
getResponseCodes(url1);
getResponseCodes(url2);
getResponseCodes(url3);
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onProgressUpdate(Integer... values) {
}
private String encodeURLString(String value) {
String encodedString = "";
try {
encodedString = URLEncoder.encode(value, "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
return encodedString;
}
public static int getResponseCodes(String TheURL) throws MalformedURLException,IOException
{
URL oUrl = new URL(TheURL);
HttpURLConnection oHuC = (HttpURLConnection) oUrl.openConnection();
oHuC.setRequestMethod("HEAD");
int response = 0;
try{
oHuC.connect();
response = oHuC.getResponseCode();
if(response == 200)
{
Log.i("URL IS OK","");
}else{
Log.i("URL IS NOT OK","");
}
Log.i("", "Status : " + response);
}catch(IOException e){
Log.d("URL ERROR" + oUrl, "D");
}
return response;
}
}
正如您所看到的,我收到回复的唯一网址是www.google.com
我的代码如下:
FixedUpdate
即使IF语句测试200 OK的响应,它也只能通过URL IS OK输出来解释来自3 URL的一个响应。