有一个edittext视图,用户应该输入有效的电子邮件地址。Click handler自动添加允许的域“@ stackoverflow.com”。我的意思是如果你点击edittext程序,java将文本设置为@ stackoverflow.com 用户输入他们的ID,如nameSurname@stackoverflow.com
问题是,如果你输入了错误的字符并再次点击edittext,它会再次设置文本@ stackoverflow.com
示例nameSrname@stackoverflow.com但您要输入nameSurname@stackoverflow.com,请单击edittext进行修复,但它再次为@ stackoverflow.com。
如何禁用第二,第三...点击事件但只启用第一次点击事件?
为什么我无法在没有点击事件的情况下设置文字?因为我不能显示提示文本。
答案 0 :(得分:0)
点击
添加验证//Define variables.
float amp = 0.0;
float freq = 0;
int totalwavelength = 50;
int mouse = 0;
void draw(){
background(0);
freq = 0;
while (freq < totalwavelength) {
//When button is not pressed, run this script:
if (mouse == 0) {
fill(255);
ellipse(freq * 50 + 20, sin(amp) * 100 + 450, 20, 20);
freq += 1;
amp += 0.5;
//Create Button
fill(255);
rect(800, 800, 200, 100);
//Mouse Coordinates
fill(255, 0, 0);
text("X=" + mouseX, mouseX, mouseY - 10);
text("Y=" + mouseY, mouseX, mouseY);
//Button script
if (mouseX >700 && mouseX < 900 && mouseY >750 && mouseY < 850 && mousePressed == true && mouse == 0) {
mouse = 1;
}
if (mouseX >700 && mouseX < 900 && mouseY >750 && mouseY < 850 && mousePressed == true && mouse == 1) {
mouse = 0;
}
}
//When button pressed run this script:
if (mouse == 1) {
fill(255);
ellipse(freq * 50 + 20, sin(amp) * 100 + 450, 20, 20);
freq += mouseX;
amp += mouseY;
//Create Button
fill(255);
rect(800, 800, 200, 100);
//Button script
if (mouseX >700 && mouseX < 900 && mouseY >750 && mouseY < 850 &&
mousePressed == true && mouse == 0) {
mouse = 1;
}
if (mouseX >700 && mouseX < 900 && mouseY >750 && mouseY < 850 &&
mousePressed == true && mouse == 1){
mouse = 0;
}
}
}
}