Question

当我尝试从数组中回显JSON对象时，它无法正常工作。在错误日志中，它给了我：

PHP Notice:  Trying to get property of non-object in /home/zadmin/test.britishweb.co.uk/patchwork/featuredseries.php on line 48

对于我尝试呼应的每一个物体。这是我的代码：

<?php

$source = "http://prod.cloud.rockstargames.com/global/SC/events/eventschedule-game-en.json"; // Source URL will be unchanged most likely but placed in a variable just in case.


$ch = curl_init(); // Connect
curl_setopt($ch, CURLOPT_URL, $source);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec ($ch);
curl_close ($ch); 

$destination = "eventschedule-game-en.json";
$file = fopen($destination, "w+");
file_put_contents($destination, $data);
fclose($file);

$json = file_get_contents($destination);

$obj = json_decode($json, true);

var_dump($obj); // Debug option

?>

$obj的转储：

{
  "multiplayerEvents": [
    {
      "posixStartTime": 1498687200,
      "posixEndTime": 1499720340,
      "eventRosGameTypes": [
        "gta5"
      ],
      "eventPlatformTypes": [
        "pcros",
        "xboxone",
        "ps4"
      ],
      "displayName": "2x$ and RP Dawn Raid Adversary Mode",
      "eventId": 20417,
      "extraData": {
        "eventType": "FeaturedJob"
      }
    }
  ]
}

然后我正在做HTML：

<div class="main_event">
    <p id="name"><?php echo $obj["displayName"]; ?> Now playing on GTA V.</p>

    <h2>Selected Platforms</h2>
    <p id="platforms">The series is currently running on the following platforms:</p>
    <ul>
        <li><?php echo $obj->eventPlatformTypes[0]; ?></li>
        <li><?php echo $obj->eventPlatformTypes[1]; ?></li>
        <li><?php echo $obj->eventPlatformTypes[2]; ?></li>

    </ul>
</div>

Answer 1

您尝试访问$obj作为对象而不是数组。您将true传递给json_decode()的第二个参数的事实告诉您返回的对象是数组而不是对象。使用与在此行访问它们相同的方式访问属性：

<p id="name"><?php echo $obj["displayName"]; ?> Now playing on GTA V.</p>

另外，请注意没有＆＃34; displayName＆＃34;在$obj。它是multiplayerEvents数组的一部分。因此，请访问您的$obj数组，如下所示：

<div class="main_event">
    <p id="name"><?php echo $obj["multiplayerEvents"][0]["displayName"]; ?> Now playing on GTA V.</p>

    <h2>Selected Platforms</h2>
    <p id="platforms">The series is currently running on the following platforms:</p>
    <ul>
        <li><?php echo $obj["multiplayerEvents"][0]["eventPlatformTypes"][0]; ?></li>
        <li><?php echo $obj["multiplayerEvents"][0]["eventPlatformTypes"][1]; ?></li>
        <li><?php echo $obj["multiplayerEvents"][0]["eventPlatformTypes"][2]; ?></li>

    </ul>
</div>

另一个小小的注意事项。如果存在可变数量的类型/事件，您可能想要遍历您的eventPlatformTypes（甚至可能是您的multiplerEvents）：

    <ul>
        <?php foreach ( $obj["multiplayerEvents"][0]["eventPlatformTypes"] as $platformType ): ?>
        <li><?php echo $platformType; ?></li>
        <?php endforeach; ?>
    </ul>

这个JSON输出我做错了什么？

1 个答案: