Question

我正在通过一个包含1000行的数据帧进行迭代。理想情况下，我想知道我的循环的进度 - 即它完成了多少行，完成了总行数的百分比等。

有没有办法可以打印行号，甚至更好，打算行的百分比？

我目前的代码如下。目前，打印它在下面看起来如何显示某种元组/列表，但我需要的只是行号。这可能很简单。

for row in testDF.iterrows():

        print("Currently on row: "+str(row))

理想的印刷回复：

Currently on row 1; Currently iterrated 1% of rows
Currently on row 2; Currently iterrated 2% of rows
Currently on row 3; Currently iterrated 3% of rows
Currently on row 4; Currently iterrated 4% of rows
Currently on row 5; Currently iterrated 5% of rows

Answer 1

如果唯一的单调索引（format），0,1,2,...的一种可能解决方案：

for i, row in testDF.iterrows():
        print("Currently on row: {}; Currently iterrated {}% of rows".format(i, (i + 1)/len(testDF.index) * 100))

样品：

np.random.seed(1332)
testDF = pd.DataFrame(np.random.randint(10, size=(10, 3)))
print (testDF)
   0  1  2
0  8  1  9
1  4  3  5
2  0  1  3
3  1  8  6
4  7  4  7
5  7  5  3
6  7  9  9
7  0  1  2
8  1  3  4
9  0  0  3

for i, row in testDF.iterrows():
        print("Currently on row: {}; Currently iterrated {}% of rows".format(i, (i + 1)/len(testDF.index) * 100))
Currently on row: 0; Currently iterrated 10.0% of rows
Currently on row: 1; Currently iterrated 20.0% of rows
Currently on row: 2; Currently iterrated 30.0% of rows
Currently on row: 3; Currently iterrated 40.0% of rows
Currently on row: 4; Currently iterrated 50.0% of rows
Currently on row: 5; Currently iterrated 60.0% of rows
Currently on row: 6; Currently iterrated 70.0% of rows
Currently on row: 7; Currently iterrated 80.0% of rows
Currently on row: 8; Currently iterrated 90.0% of rows
Currently on row: 9; Currently iterrated 100.0% of rows

编辑：

如果某些自定义索引值，zip和numpy.arange length of index的解决方案与length of df的内容相同，则为np.random.seed(1332) testDF = pd.DataFrame(np.random.randint(10, size=(10, 3)), index=[2,4,5,6,7,8,2,1,3,5]) print (testDF) 0 1 2 2 8 1 9 4 4 3 5 5 0 1 3 6 1 8 6 7 7 4 7 8 7 5 3 2 7 9 9 1 0 1 2 3 1 3 4 5 0 0 3 for i, (idx, row) in zip(np.arange(len(testDF.index)), testDF.iterrows()): print("Currently on row: {}; Currently iterrated {}% of rows".format(idx, (i + 1)/len(testDF.index) * 100)) Currently on row: 2; Currently iterrated 10.0% of rows Currently on row: 4; Currently iterrated 20.0% of rows Currently on row: 5; Currently iterrated 30.0% of rows Currently on row: 6; Currently iterrated 40.0% of rows Currently on row: 7; Currently iterrated 50.0% of rows Currently on row: 8; Currently iterrated 60.0% of rows Currently on row: 2; Currently iterrated 70.0% of rows Currently on row: 1; Currently iterrated 80.0% of rows Currently on row: 3; Currently iterrated 90.0% of rows Currently on row: 5; Currently iterrated 100.0% of rows：

self.view

Answer 2

首先iterrows给出了(index, row)的元组。所以正确的代码是

for index, row in testDF.iterrows():

一般情况下索引不是一个行数，它是一些标识符（这是大熊猫的力量，但它会产生一些混淆，因为它在python中的行为不像普通list那里索引是数字排）。这就是我们需要独立计算行数的原因。我们可以引入line_number = 0并在每个cirlce line_number += 1中增加它。但是python为我们提供了一个现成的工具：enumerate，它返回(line_number, value)而不是value的元组。所以我们来看看那段代码

for (line_number, (index, row)) in enumerate(testDF.iterrows()):
    print("Currently on row: {}; Currently iterrated {}% of rows".format(
          line_number, 100*(line_number + 1)/len(testDF)))

P.S。当你设置integeres时，python2会返回整数，这就是为什么999/1000 = 0，你不期望的。因此，您可以采用更好的浮动或将100*带到开头以获得整数百分比。

Answer 3

对于大数据帧，限制打印可能更好，这是一项耗时的任务。这是一种方法：

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Pandas Iterrows Row Number＆amp;百分比

3 个答案: