Question

我有一个对象数组的数据，如下所示。

Array(

    [0]=>Object(
      [event_day]=>Tuesday
    )

    [1]=>Object(
      [event_day]=>Friday
    )

   [2]=>Object(
      [event_day]=>Wednesday
   ) 
 )

我需要根据从星期一开始的工作日来排序，如下所示：

Array(

    [0]=>Object(
      [event_day]=>Tuesday
    )

    [1]=>Object(
      [event_day]=>Wednesday
    )

   [2]=>Object(
      [event_day]=>Friday
   ) 
 )

Answer 1

对数据进行排序的代码：

$dataToSort = [
    (object)['event_day' => 'Tuesday'],
    (object)['event_day' => 'Friday'],
    (object)['event_day' => 'Wednesday'],
];

$dayOrder = [
    'Monday'    => 1,
    'Tuesday'   => 2,
    'Wednesday' => 3,
    'Thursday'  => 4,
    'Friday'    => 5,
    'Saturday'  => 6,
    'Sunday'    => 7,
];

usort($dataToSort,
    function ($a, $b) use ($dayOrder) {
        return $dayOrder[$a->event_day] > $dayOrder[$b->event_day];
    });

print_r($dataToSort);

输出：

Array
(
    [0] => stdClass Object
        (
            [event_day] => Tuesday
        )

    [1] => stdClass Object
        (
            [event_day] => Wednesday
        )

    [2] => stdClass Object
        (
            [event_day] => Friday
        )

)

通过这种方式，您可以对任何事情进行排序，而不仅仅是几天。

Answer 2

使用usort和array_search函数的解决方案：

// predefined weekdays list (in order)
$weekdays = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];

// $arr is your initial array    
usort($arr, function($a, $b) use($weekdays){
   return array_search($a->event_day, $weekdays) - array_search($b->event_day, $weekdays);
});

print_r($arr);

按周计算对象数组

2 个答案: