如何消除'onmessage'的时间延迟

Question

主要目标是与工作者进行主线程的最快（> 200fps）消息交换，无论该选项卡是否处于活动状态。

示例：

工人代码：

onmessage = function(rawMsg) {
    var msg = rawMsg.data;

    msg.state = "worker-THREAD:setInterval=>main-THREAD:onmessage=>worker-THREAD:onmessage";
    msg.times.push( performance.now() );

    postMessage(msg);
}

var sequenceNum = 0;

setInterval(function() {
    var msg = {state:"", times: [], sequenceNum: sequenceNum++};

    msg.state = "worker-THREAD:setInterval";
    msg.times.push( performance.now() );

    postMessage(msg);
}, 100);

主线程代码：

var worker = new Worker( 'js/test-worker.js' );

worker.onmessage = function(rawMsg) {
    var msg = rawMsg.data;

    switch( msg.state ) {
        case "worker-THREAD:setInterval":
            msg.state = "worker-THREAD:setInterval=>main:thread:onmessage";
            msg.times.push( performance.now() );

            worker.postMessage(msg);
            break;

        case "worker-THREAD:setInterval=>main-THREAD:onmessage=>worker-THREAD:onmessage":
            show(msg);
            break;
    }
}

var lastSequenceNum = 0;
function show(msg) {
    msg.times = msg.times.map(function(val) { return val / 1e3 });

    if ( lastSequenceNum++ !== msg.sequenceNum ) {
        alert("error sequence");
    }

    var ping = msg.times[2] - msg.times[0];

    var isBad = ( ping > 0.01 );

    var fx = 3;

    var times = msg.times.map(function(val) { return val.toFixed(fx) });

    console.log('#' + msg.sequenceNum + ' [ ' + times.join(', ') + ' ] ' + ping.toFixed(fx) + (isBad?' BAD!!!': ''));
}

  var worker_Code = `
    onmessage = function(rawMsg) {
      var msg = rawMsg.data;

      msg.state = "worker-THREAD:setInterval=>main-THREAD:onmessage=>worker-THREAD:onmessage";
      msg.times.push( performance.now() );

      postMessage(msg);
    }

    var sequenceNum = 0;

    setInterval(function() {
      var msg = {state:"", times: [], sequenceNum: sequenceNum++};

      msg.state = "worker-THREAD:setInterval";
      msg.times.push( performance.now() );

      postMessage(msg);
    }, 100);
  `;

  var worker = new Worker( window.URL.createObjectURL( new Blob( [worker_Code] ) ) );

	worker.onmessage = function(rawMsg) {
		var msg = rawMsg.data;

		switch( msg.state ) {
			case "worker-THREAD:setInterval":
				msg.state = "worker-THREAD:setInterval=>main:thread:onmessage";
				msg.times.push( performance.now() );

				worker.postMessage(msg);
				break;

			case "worker-THREAD:setInterval=>main-THREAD:onmessage=>worker-THREAD:onmessage":
				show(msg);
				break;
		}
	}

	var lastSequenceNum = 0;
	function show(msg) {
		msg.times = msg.times.map(function(val) { return val / 1e3 });

		if ( lastSequenceNum++ !== msg.sequenceNum ) {
			alert("error sequence");
		}

		var ping = msg.times[2] - msg.times[0];

		var isBad = ( ping > 0.01 );

		var fx = 3;

		var times = msg.times.map(function(val) { return val.toFixed(fx) });

		console.log('#' + msg.sequenceNum + ' [ ' + times.join(', ') + ' ] ' + ping.toFixed(fx) + (isBad?' BAD!!!': ''));
	}

在jsfiddle https://jsfiddle.net/03pfwmt9/

如果标签未处于活动状态，则消息会累积，并且一秒钟内就会出现“onmessage”。 我该如何解决这个问题？