Question

我在草图中有一个问题，有12个LED和4个按钮，其中按住按钮可以关闭某些LED。我用一个LED和一个按钮做了一个更基本的草图来展示我的问题，但这个基本草图完美无缺！所以我想知道为什么我的基本示例（草图1）工作得很好但是LED在我更复杂的例子（草图2）中闪烁，好吗？

SKETCH 1（效果很好）：

//sets up button and LED connections:
const int led_1 = 4;
const int but_1 = 8;

//sets up variable butState that will be changed later
int butState;

void setup() {
  //sets pin modes:
  pinMode(led_1, OUTPUT);
  pinMode(but_1, INPUT);
}

void loop() {
  //variable that reads the button state:
  butState = digitalRead(but_1);

  //if the button state is high, sets LED state low. Opposite if button state is low:
  if (butState == HIGH) {
    delay(200);
    digitalWrite(led_1, LOW);
  }
  else {
    delay(200);
    digitalWrite(led_1, HIGH);
  }
}

SKETCH 2（LED闪烁）：

//turns all lights on. turns in1 lights off when button 1 pressed.
//turns in2 lights off when second button is pressed.
//turns out lights off when third button is pressed
//turns all lights off when fourth button pressed

//result (output) lights:
const int res_8 = A5;
const int res_4 = A4;
const int res_2 = A3;
const int res_0 = A2;

//in1 lights:
const int in1_4 = 4;
const int in1_2 = 3;
const int in1_0 = 2;

//in2 lights:
const int in2_4 = 7;
const int in2_2 = 6;
const int in2_0 = 5;

//input buttons:
const int b_4 = 8;
const int b_2 = 9;
const int b_0 = 10;
const int b_enter = 11;

// set up switch states
int b4State = 0;
int b2State = 0;
int b0State = 0;
int benterState = 0;

 void setup() {
  // set up pins
  pinMode(res_8, OUTPUT);
  pinMode(res_4, OUTPUT);
  pinMode(res_2, OUTPUT);
  pinMode(res_0, OUTPUT);
  pinMode(in1_4, OUTPUT);
  pinMode(in1_2, OUTPUT);
  pinMode(in1_0, OUTPUT);
  pinMode(in2_4, OUTPUT);
  pinMode(in2_2, OUTPUT);
  pinMode(in2_0, OUTPUT);
  pinMode(b_4, INPUT);
  pinMode(b_2, INPUT);
  pinMode(b_0, INPUT);
  pinMode(b_enter, INPUT);
}

void loop() {
  //reads the state of button inputs
  b4State = digitalRead(b_4);
  b2State = digitalRead(b_2);
  b0State = digitalRead(b_0);
  benterState = digitalRead(b_enter);
  //checks button 1
  if (b4State == HIGH) {
    delay(1000);
    digitalWrite(in1_4, LOW);
    digitalWrite(in1_2, LOW);
    digitalWrite(in1_0, LOW);
  }
  else {
  delay(1000);
  digitalWrite(in1_4, HIGH);
  digitalWrite(in1_2, HIGH);
  digitalWrite(in1_0, HIGH);
  }

  //checks button 2
  if (b2State == HIGH) {
    delay(1000);
    digitalWrite(in2_4, LOW);
    digitalWrite(in2_2, LOW);
    digitalWrite(in2_0, LOW);
  }
  else {
  delay(1000);
  digitalWrite(in2_4, HIGH);
  digitalWrite(in2_2, HIGH);
  digitalWrite(in2_0, HIGH); 
  }

  //checks button 3
  if (b0State == HIGH) {
    delay(1000);
    analogWrite(res_8, 0);
    analogWrite(res_4, 0);
    analogWrite(res_2, 0);
    analogWrite(res_0, 0);
  }
  else {
  delay(1000);
  analogWrite(res_8, 1023);
  analogWrite(res_4, 1023);
  analogWrite(res_2, 1023);
  analogWrite(res_0, 1023);
  }

  //checks enter button
  if (benterState == HIGH) {
    delay(1000);
    digitalWrite(in1_4, LOW);
    digitalWrite(in1_2, LOW);
    digitalWrite(in1_0, LOW);
    digitalWrite(in2_4, LOW);
    digitalWrite(in2_2, LOW);
    digitalWrite(in2_0, LOW);
    analogWrite(res_8, 0);
    analogWrite(res_4, 0);
    analogWrite(res_2, 0);
    analogWrite(res_0, 0);
  }
  else {
  delay(1000);
  analogWrite(res_8, 1023);
  analogWrite(res_4, 1023);
  analogWrite(res_2, 1023);
  analogWrite(res_0, 1023);
  digitalWrite(in1_4, HIGH);
  digitalWrite(in1_2, HIGH);
  digitalWrite(in1_0, HIGH);
  digitalWrite(in2_4, HIGH);
  digitalWrite(in2_2, HIGH);
  digitalWrite(in2_0, HIGH);
  }

//  //delays
//  delay(250);
}

感谢您的帮助！

Answer 1

问题出在你的考试中。

  //checks button 1
  if (b4State == HIGH) {
    // turn LEDs on for 1 second
  }
  else {
    /* turn LEDs off 1 sec */         // button 4 released -> LEDs OFF, 
    /* even if button 2 is pushed! */ // even when button 2 is pushed
  }

  //checks button 2
  if (b2State == HIGH) 
  {
     // turn LEDs on 1 second
  }
  else 
  {
     // turn LEDs off 1 sec - 
     // even when button 4 is pushed!
  }

你想要的逻辑：

  //checks button 1
  if (b4State == HIGH)  
  {
    delay(1000);
    digitalWrite(in1_4, LOW);
    digitalWrite(in1_2, LOW);
    digitalWrite(in1_0, LOW);
  }
  else if (b2State == HIGH)            // button 4 is not pushed... check button 2
  {
    delay(1000);                      
    digitalWrite(in2_4, LOW);
    digitalWrite(in2_2, LOW);
    digitalWrite(in2_0, LOW);
  }
  else 
  {
    delay(1000);                       // only turn off the LED when both buttons
    digitalWrite(in2_4, HIGH);         // are released
    digitalWrite(in2_2, HIGH);
    digitalWrite(in2_0, HIGH); 
  }

按下按钮2和4会在您发布的代码中产生相同的效果，因此测试可以简化为简单的if / else，但我认为您可能计划在应用中添加更多代码。

当有多个LED /按钮时，LED会闪烁而不是保持开/关状态？

1 个答案: