Question

假设我有以下字符串：

Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing and typesetting industry

我想得到tag1和tag2之间的子串，因此

is simply dummy text of

我怎么能用Ruby做到这一点？

Answer 1

试试这个：

str = "Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing and typesetting industry"


str[/\(tag1\)(.*?)\(tag2\)/m, 1]
# => " is simply dummy text of"

Answer 2

尝试String#split

str = "Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing and typesetting industry"
str.split(/\(tag2\)|\(tag1\)/)[1]
#=>"is simply dummy text of"

Answer 3

您可以使用REGEX的capturing technique。让我解释一下：

> str = "Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing and typesetting industry"

> a = str.match /\(tag1\)(.*)\(tag2\)/
=> #<MatchData "(tag1) is simply dummy text of(tag2)" 1:" is simply dummy text of">

> a[1]
=> " is simply dummy text of"

在这里，我使用\(或\)转义字符串中的括号，因为REGEX引擎可能会因为它具有特殊含义而感到困惑。

接下来，(.*)引用capture所有长度为any的字符。任何都由*（Asterisk）隐含。

一般情况下，它会匹配你所拥有的两个单词之间的所有字符作为开始＆amp;终点。

Answer 4

非正则表达式解决方案：

str = "Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing industry"

str[str.index("(tag1)")+6..str.index("(tag2)")-1]
  #=> " is simply dummy text of"

Answer 5

您可以使用lookbehind和lookahead并在以下文本之间捕获文本：

> st='Lorem Ipsum(tag1) is simply dummy text of(tag2) the printing and typesetting industry'
> st[/(?<=tag\d\) ).*?(?=\(tag\d)/]
=> "is simply dummy text of"

在substring1之后和substring2之前获取字符串

5 个答案: