我有三个下拉菜单: -
<select clas="col-md-3" ng-model="a.userList" ng-change="selectValues(a.userList)">
<option>AX</option>
<option>AF</option>
<option>AM</option>
<option>BX</option>
<option>BF</option>
<option>BM</option>
<option>CX</option>
<option>CF</option>
<option>CM</option>
<option>DX</option>
<option>DF</option>
<option>DM</option>
</select>
<select clas="col-md-3" ng-model="a.userCode">
<option>A</option>
<option>B</option>
<option>C</option>
<option>D</option>
</select>
<select clas="col-md-3" ng-model="a.userId">
<option>X</option>
<option>F</option>
<option>M</option>
</select>
我想要的是当用户选择AX
然后从其他两个下拉列表中分别选择A和X,并从这两个下拉列表中删除所有其他值。
我的指令代码: -
scope.selectValues = function(userList){
switch(userList){
case "AX" : scope.a.userCode = "A";
scope.a.userId = "X";
break;
case "AF" : scope.a.userCode = "A";
scope.a.userId = "F";
break;
case "AM" : scope.a.userCode = "A";
scope.a.userId = "M";
break;
};
};
在上面的代码中,我能够选择我想要选择的特定值,但是无法从两个下拉列表中删除所有其他值。任何人都可以告诉我如何从下拉列表中删除值。
答案 0 :(得分:1)
您应该将选项放在范围内!
<强> JS 强>
scope.userList = ["AX","AF", "AM", "BX", "BF"];
//Obviously put all of your options in this array also for the other selects
scope.userCode = [....];
scope.userId = [....];
<强> HTML 强>
你需要ng-options
<select class="col-md-3" ng-model="a.userList"
ng-options="option for option in topUserList track by $index"
ng-change="selectValues(a.userList)"></select>
JS
scope.selectValues = function(userList){
scope.a.userCode = userList.charAt(0);
scope.a.userId = userList.charAt(1);
scope.userCode = [scope.a.userCode];
scope.userId = [scope.a.userId];
};