在Vaadin 8.1 TreeGrid中替换collapseItemsRecursively和expandItemsRecursively

时间:2017-07-01 12:09:15

标签: vaadin vaadin8

Vaadin 8.1介绍了TreeGrid组件。它不再具有collapseItemsRecursivelyexpandItemsRecursively方法(现在在旧版Tree组件中可用)。我是否会遗漏某些内容,或者您​​是否需要开发自己的实现?如果是这样,建议的方法是什么?

2 个答案:

答案 0 :(得分:2)

我确信您已经注意到,TreeGrid是一个相当新的组件,目前正在开发并从v8.1.alphaX开始提供(当前稳定版本为v8.0.6)。因此,它可能暂时只有一些基本功能,其余的将在未来的某个时间进行,尽管不能保证。例如,this similar feature request for the older TreeTable component自2011年以来一直处于开放状态。

Vaadin docs warning

无论哪种方式,即使它们可能不是最佳解决方案,也可以使用一些解决方法来实现此行为。我使用无耻地作为基本样本使用了vaadin-sampler for TreeGrid中当前可用代码的略微修改版本。

public class RecursiveExpansionTreeGrid extends VerticalLayout {

    private Random random = new Random();

    public RecursiveExpansionTreeGrid() {
        // common setup with some dummy data
        TreeGrid<Project> treeGrid = new TreeGrid<>();
        treeGrid.setItems(generateProjectsForYears(2010, 2016), Project::getSubProjects);
        treeGrid.addColumn(Project::getName).setCaption("Project Name").setId("name-column");
        treeGrid.addColumn(Project::getHoursDone).setCaption("Hours Done");
        treeGrid.addColumn(Project::getLastModified).setCaption("Last Modified");
        addComponent(treeGrid);
    }

    // generate some dummy data to display in the tree grid
    private List<Project> generateProjectsForYears(int startYear, int endYear) {
        List<Project> projects = new ArrayList<>();

        for (int year = startYear; year <= endYear; year++) {
            Project yearProject = new Project("Year " + year);

            for (int i = 1; i < 2 + random.nextInt(5); i++) {
                Project customerProject = new Project("Customer Project " + i);
                customerProject.setSubProjects(Arrays.asList(
                        new LeafProject("Implementation", random.nextInt(100), year),
                        new LeafProject("Planning", random.nextInt(10), year),
                        new LeafProject("Prototyping", random.nextInt(20), year)));
                yearProject.addSubProject(customerProject);
            }
            projects.add(yearProject);
        }
        return projects;
    }

    // POJO for easy binding
    public class Project {
        private List<Project> subProjects = new ArrayList<>();
        private String name;

        public Project(String name) {
            this.name = name;
        }

        public String getName() {
            return name;
        }

        public List<Project> getSubProjects() {
            return subProjects;
        }

        public void setSubProjects(List<Project> subProjects) {
            this.subProjects = subProjects;
        }

        public void addSubProject(Project subProject) {
            subProjects.add(subProject);
        }

        public int getHoursDone() {
            return getSubProjects().stream().map(project -> project.getHoursDone()).reduce(0, Integer::sum);
        }

        public Date getLastModified() {
            return getSubProjects().stream().map(project -> project.getLastModified()).max(Date::compareTo).orElse(null);
        }
    }

    // Second POJO for easy binding
    public class LeafProject extends Project {
        private int hoursDone;
        private Date lastModified;

        public LeafProject(String name, int hoursDone, int year) {
            super(name);
            this.hoursDone = hoursDone;
            lastModified = new Date(year - 1900, random.nextInt(12), random.nextInt(10));
        }

        @Override
        public int getHoursDone() {
            return hoursDone;
        }

        @Override
        public Date getLastModified() {
            return lastModified;
        }
    }
}

接下来,递归地扩展或折叠节点取决于您的场景,但基本上它分解为相同的事情:确保从根到最深的叶子的每个节点都被展开/折叠。最简单的方法是将您的层次结构展平到一个节点列表中,并调用适当的方法expand(List<T> items)expand(T ... items)(第二个委托给第一个,可能是一个方便的方法,例如{ {1}})。

为简单起见,我在expand(myItem)实施中添加了flatten方法。如果由于某种原因你不能这样做,那么创建一个递归方法,创建一个以所选节点开始的列表,并包括孩子们的所有孩子,孩子们......好吧,你明白了

Project

可能的情况:

  1. 展开根目录时自动展开整个层次结构 - 添加侦听器,展开/折叠整个展平层次结构:
  2. public Stream<Project> flatten() {
        return Stream.concat(Stream.of(this), getSubProjects().stream().flatMap(Project::flatten));
    }
    
    1. 使用自定义操作(例如上下文菜单)
    2. 扩展层次结构或部分层次结构
      treeGrid.addCollapseListener(event -> {
          if (event.isUserOriginated()) {
              // event is triggered by all collapse calls, so only do it the first time, when the user clicks in the UI
              // and ignore the programmatic calls
              treeGrid.collapse(event.getCollapsedItem().flatten().collect(Collectors.toList()));
          }
      });
      treeGrid.addExpandListener(event -> {
          if (event.isUserOriginated()) {
              // event is triggered by all expand calls, so only do it the first time, when the user clicks in the UI
              // and ignore the programmatic calls
              treeGrid.expand(event.getExpandedItem().flatten().collect(Collectors.toList()));
          }
      });
      

      最后,你应该得到这个效果:

      TreeGrid - expand or collapse recursively

答案 1 :(得分:0)

docs for treegrid开始,您可以使用方法collapseexpand,通过传递treegrid数据项的列表或数组来展开或折叠:

treeGrid.expand(someTreeGridItem1, someTreeGridItem2);
treeGrid.collapse(someTreeGridItem1);

另外值得注意的是,该部分显示了prevent certain items from ever being collapsed

的能力