Question

我的这个列表包含部分语音标签及其细节：['VNW(pers,pron,nomin,red,2v,ev)', 'WW(pv,tgw,met-t)', 'LID(bep,stan,rest)']。如您所见，角色之间没有空格，因此可以将其视为一个单词。

现在我需要一个只包含部分语音标签的新列表，例如['VNW', 'WW', 'LID']。我尝试使用像pattern = re.compile(r'(.*)')这样的正则表达式删除括号及其中的所有内容我也试图只匹配大写字母，但我无法做到正确。建议？

Answer 1

这种情况不需要正则表达式。按import UIKit import AVFoundation class CameraViewController: UIViewController, AVCaptureMetadataOutputObjectsDelegate { @IBOutlet weak var messageView: UIView! @IBOutlet weak var messageLbl: UILabel! @IBOutlet weak var topBar: UIView! var captureSession: AVCaptureSession? var videoPreviewLayer: AVCaptureVideoPreviewLayer? var qrCodeFrameView: UIView? override func viewDidLoad() { super.viewDidLoad() let captureDevice = AVCaptureDevice.defaultDevice(withMediaType: AVMediaTypeVideo) do { let input = try AVCaptureDeviceInput(device: captureDevice) as AVCaptureDeviceInput captureSession = AVCaptureSession() captureSession?.addInput(input) } catch { print(error) return } let captureMetaDataOutput = AVCaptureMetadataOutput() captureSession?.addOutput(captureMetaDataOutput) captureMetaDataOutput.setMetadataObjectsDelegate(self, queue: DispatchQueue.main) captureMetaDataOutput.metadataObjectTypes = [AVMetadataObjectTypeQRCode] videoPreviewLayer = AVCaptureVideoPreviewLayer(session: captureSession) videoPreviewLayer?.videoGravity = AVLayerVideoGravityResizeAspectFill videoPreviewLayer?.frame = view.layer.bounds view.layer.addSublayer(videoPreviewLayer!) captureSession?.startRunning() view.bringSubview(toFront: messageLbl) view.bringSubview(toFront: topBar) view.bringSubview(toFront: messageView) qrCodeFrameView = UIView() if let newFrame = qrCodeFrameView { newFrame.layer.borderColor = UIColor.green.cgColor newFrame.layer.borderWidth = 2 view.addSubview(newFrame) view.bringSubview(toFront: newFrame) } } func captureOutput(_ captureOutput: AVCaptureOutput!, didOutputMetadataObjects metadataObjects: [Any]!, from connection: AVCaptureConnection!) { if metadataObjects == nil || metadataObjects.count == 0 { qrCodeFrameView?.frame = CGRect.zero messageLbl.text = "No QR code is detected" return } let metadataObj = metadataObjects[0] as! AVMetadataMachineReadableCodeObject if metadataObj.type == AVMetadataObjectTypeQRCode { let barCodeObject = videoPreviewLayer?.transformedMetadataObject(for: metadataObj) qrCodeFrameView?.frame = barCodeObject!.bounds if metadataObj.stringValue != nil { messageLbl.text = metadataObj.stringValue } } } @IBAction func goToList(_ sender: Any) { self.dismiss(animated: true, completion: nil) } }拆分;然后只获得第一部分。

class MovieListViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {


    @IBOutlet weak var movieTableView: UITableView!



    var movie:[Movie] = [Movie]()
    var currentMovies:[Movie] = [Movie]()
    var counter = 0

    override func viewDidLoad() {
        super.viewDidLoad()

        movie = Helpers.downloadJson()
        self.movieTableView.reloadData()
        sort()

    }

    func sort() {
        movie.sort(by: { $0.releaseYear < $1.releaseYear })
        movieTableView.reloadData()

    }

    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return movie.count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "MovieCell") as! MovieCell

        cell.createCell(movie: movie[indexPath.row])

        return cell
    }

    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        let selectedMovie = movie[indexPath.row]
        performSegue(withIdentifier: "goToDetail", sender: selectedMovie)
    }

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        let nextVC = segue.destination as! DetailViewController
        nextVC.movie = sender as! Movie
    }

    @IBAction func addTapped(_ sender: Any) {
        let storyBoard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
        let nextView = storyBoard.instantiateViewController(withIdentifier: "goToCamera") as! CameraViewController
        self.present(nextView, animated: true, completion: nil)

    }

}

Answer 2

一些可能的解决方案是：

使用循环删除括号

l = ['VNW(pers,pron,nomin,red,2v,ev)', 'WW(pv,tgw,met-t)', 'LID(bep,stan,rest)']
for i in range(len(l)):
    i1,i2=l[i].find('('),l[i].find(')')
    l[i]=l[i][:i1]+l[i][i2+1:]
print l

使用正则表达式

import re
pattern = r'\([^)]*\)'
l = ['VNW(pers,pron,nomin,red,2v,ev)', 'WW(pv,tgw,met-t)', 'LID(bep,stan,rest)']
for i in range(len(l)):
    l[i] = re.sub(pattern, '', l[i])
print l

输出： [＆＃39; VNW＆＃39;，＆＃39; WW＆＃39;，＆＃39; LID＆＃39;]

Answer 3

使用str.find()函数的简短解决方案：

l = ['VNW(pers,pron,nomin,red,2v,ev)', 'WW(pv,tgw,met-t)', 'LID(bep,stan,rest)']
result = [i[:i.find('(')] for i in l]

result内容：

['VNW', 'WW', 'LID']

Answer 4

例如：

In [102]: s=['VNW(pers,pron,nomin,red,2v,ev)', 'WW(pv,tgw,met-t)', 'LID(bep,stan,rest)']
In [103]: [x.split('(', 1)[0] for x in s]
Out[103]: ['VNW', 'WW', 'LID']

删除一个单词＆＃39;字符串Python

4 个答案: