Question

这不会产生语法错误但会产生错误的参数错误：

SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
  IIF(instr([aname], ",") = 0,
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))
&  ","  &

right(
   [aname],
 IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
    IIF(instr([aname], ",") = 0,
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],",")))))
 &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON (right(FinalForgotten.aname,
 IIF(instr([aname], ",") = 0,
 Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
 Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")
  )
 )=defense_final.first_name) AND (left(FinalForgotten.aname,
IIF(instr([aname], ",") = 0,
  InStr(1,FinalForgotten.[aname]," ")-1,
  InStr(1,FinalForgotten.[aname],",")-1
    )
)=defense_final.last_name);

所以添加额外的参数我现在得到语法错误“Missing”，]或查询表达式中的Item“：

   SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
  IIF(instr([aname], ",") = 0,
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))
&  ","  &

right(
   [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
    IIF(instr([aname], ",") = 0,
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],","))))
 &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname,
   IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
      Len(FinalForgotten.aname),
      IIF(instr([aname], ",") = 0,
        InStr(1,FinalForgotten.[aname]," ")-1,
        InStr(1,FinalForgotten.[aname],",")-1)))

 =defense_final.last_name AND 

 right(FinalForgotten.aname,
      IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
      Len(FinalForgotten.aname),
       IIF(instr([aname], ",") = 0,
        Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
        Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))))

=defense_final.first_name;

任何解决方法？

感谢您的回复。

Answer 1

第10行

right(

没有相应的右括号

Answer 2

SELECT left( [aname], 所以[aname]是一个文本字段。

 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

如果此条件为真，则希望Left String的长度为：

 FinalForgotten.aname,

哪个不是整数。你想要：

SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),

Answer 3

 IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0,

第12行的

应为

 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

Answer 4

将该逻辑放入VBA函数会更容易，因此查询看起来像这样

SELECT GetFullNameWithMiddle([aname]) AS fullname
INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final
    ON GetLastName([aname])=defense_final.last_name
    AND GetFirstName([aname])=defense_final.first_name

由于您说您不想使用VBA，请尝试使用此选项。我附上了每一个

InStr(x, y) = 0

在括号中

，所以

IIf(InStr(x, y) = 0 AND InStr(p, q) = 0, g, h)

变为

IIf((InStr(x, y) = 0) AND (InStr(p, q) = 0), g, h)

进行更改后，我可以切换到查询设计网格，这意味着SQL解析器喜欢它：

SELECT left(
    [aname],
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))

    &  ","  &

right(
    [aname],
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],","))))

    &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname,
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    InStr(1,FinalForgotten.[aname]," ")-1,
    InStr(1,FinalForgotten.[aname],",")-1)))

=defense_final.last_name AND 

right(FinalForgotten.aname,
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))))

=defense_final.first_name;

查询表达式中的语法错误（缺少运算符） - MS-Access

4 个答案: