我的数据格式如下:
["DATA1-1","DATA1-2","DATA1-3","DATA1-4","","DATA2-1","DATA2-2","DATA2-3","DATA2-4","","DATA3-1","DATA3-2","DATA3-3","DATA3-4",""]
我想将这个数组拆分成几个数组,其中分隔符应该是一个空项("")。像这样:
[["DATA1-1","DATA1-2","DATA1-3","DATA1-4"],["DATA2-1","DATA2-2","DATA2-3","DATA2-4"],["DATA3-1","DATA3-2","DATA3-3","DATA3-4"]].
这是我提出的代码:
private List<List<String>> retrieveData(List<String> arrayIn)
{
List<List<String>> subArrays = new ArrayList<>();
List<String> tempArrays = new ArrayList<>();
for(int i=0; i<arrayIn.size(); i++)
{
if(!airwayIn.get(i).equals("") && i != (airwayIn.size()-1) )
{
tempArrays.add(airwayIn.get(i));
}
else if (airwayIn.get(i).equals("") || i == (airwayIn.size()-1) )
{
subArrays.add(tempArrays);
tempArrays = new ArrayList<>();
}
}
return subArrays;
}
但我想知道是否有更优雅的代码可以做到这一点。例如,这是我在Swift中使用的:
let subArrays: [[String]] = airwayIn.split(separator: "").map{Array($0)}
谢谢!
答案 0 :(得分:0)
这是使用Java 8的解决方案:
private List<List<String>> retrieveData (List<String> list)
{
// get all the indexes of the empty strings
int [] indexes =
Stream.of(IntStream.of(-1), IntStream.range(0, list.size())
.filter(i -> list.get(i).equals("")), IntStream.of(list.size()))
.flatMapToInt(s -> s).toArray();
// Split into sub lists based on the indexes
List<List<String>> subLists =
IntStream.range(0, indexes.length - 2)
.mapToObj(i -> list.subList(indexes[i] + 1, indexes[i + 1]))
.collect(Collectors.toList());
System.out.println(subLists);
return subLists;
}
<强>输出强>:
[[DATA1-1, DATA1-2, DATA1-3, DATA1-4], [DATA2-1, DATA2-2, DATA2-3, DATA2-4], [DATA3-1, DATA3-2, DATA3-3, DATA3-4]]
答案 1 :(得分:0)
您可以使用简单的for
循环来执行此操作,例如:
String[] array = {"DATA1-1","DATA1-2","DATA1-3","DATA1-4","","DATA2-1","DATA2-2","DATA2-3","DATA2-4","","DATA3-1","DATA3-2","DATA3-3","DATA3-4",""};
List<List<String>> result = new ArrayList<>();
List<String> elements = new ArrayList<>();
for(String s : array){
if("".equals(s) && !elements.isEmpty()){
result.add(elements);
elements = new ArrayList<>();
}else{
elements.add(s);
}
}
//Add the remaining elements
if(!elements.isEmpty()){
result.add(elements);
}
System.out.println(result);