Question

我想在一行中搜索并匹配任何单词后跟文件扩展名.log.gz，并仅打印匹配的单词。

以下是我尝试过的代码示例

# Global Import Variables
import Tkinter, Tkconstants, tkFileDialog

line = "helo how are helloo.log.gz you"

line_se = re.search(r"\b.*\.log.gz", line)


if line_se:
    print line_se
    print("yo it's a {}".format(line_se.group(0)))

但输出是整行，直到扩展为止 yo it's a helo how are helloo.log.gz，但我想要的输出只是helloo.log.gz。任何人都可以在reg exp上纠正我，我用它来打印出带扩展名的匹配单词！

非常感谢！

Answer 1

将.*更改为\S*，使其与空格不匹配。

ine_se = re.search(r"\S*\.log\.gz", line)

Answer 2

你实际上不需要正则表达式。内置的字符串方法就足够了。例如，

from functools import partial

def find_filename(text, extension):
    """Finds the first word in 'text' that ends with 'extension.',
    or 'None' if 'text' doesn't contain such a word."""
    words = text.split()
    for word in words:
        if word.endswith('.' + extension):
            return word

find_log_gz = partial(find_filename, extension="log.gz")

# Test:
>>> find_log_gz("helo how are helloo.log.gz you")
'helloo.log.gz'
>>>

如何匹配任何带有文件扩展名的字符串，并在python中仅打印匹配的单词

2 个答案: