Question

如果检测到标点符号（。？！）并且在没有空格的两个单词之间发生，我怎样才能分割句子？

实施例

>>> splitText = re.split("(?<=[.?!])\s+", "This is an example. Not 
    working as expected.Because there isn't a space after dot.")

输出：

['This is an example.', 
"Not working as expected.Because there isn't a space after dot."]

预期：

['This is an example.', 
'Not working as expected.', 
'Because there isn't a space after dot.']`

Answer 1

splitText = re.split("[.?!]\s*", "This is an example. Not working as expected.Because there isn't a space after dot.")

+用于1个或更多的东西，*用于零个以上。

如果你需要保留。你可能不想拆分，而是你可以这样做：

splitText = re.findall(".*?[.?!]", "This is an example. Not working as expected.Because there isn't a space after dot.")

给出了

['This is an example.',
 ' Not working as expected.',
 "Because there isn't a space after dot."]

您可以通过使用正则表达式（例如'\s*.*?[.?!]'）或仅使用.trim()来修剪它们

Answer 2

使用 https://regex101.com/r/icrJNl/3/

import re
from pprint import pprint

split_text = re.findall(".*?[?.!]", "This is an example! Working as "
                        "expected?Because.")

pprint(split_text)

注意：.*?是一个与.*相反的懒惰（或非贪婪）量词，这是一个贪婪的量词。

输出：

['This is an example!', 
 ' Working as expected?', 
 'Because.']

另一种解决方案：

import re
from pprint import pprint

split_text = re.split("([?.!])", "This is an example! Working as "
    "expected?Because.")

pprint(split_text)

输出：

['This is an example', 
'!', 
' Working as expected', 
'?', 
'Because', 
'.', 
'']

没有空格的单词之间没有检测到标点符号

2 个答案: