Question

我正在尝试创建一个方法，该方法使用对象的每个成员生成JobParameters对象。这是我到目前为止所得到的：

public static JobParameters getAttributesAsJobParameters(Object objectToConvert) throws IllegalAccessException {
    JobParametersBuilder jobParametersBuilder = new JobParametersBuilder();

    for (Field field : objectToConvert.getClass().getDeclaredFields()) {
        field.setAccessible(true);
        jobParametersBuilder.addLong(field.getName(), (Long) field.get(objectToConvert));
    }

    return jobParametersBuilder.toJobParameters();
}

但是只有当对象没有任何与Long不同的成员时，这才有效。我怎样才能使其适用于所有原始类型？

Answer 1

根据https://docs.oracle.com/javase/tutorial/reflect/member/fieldTypes.html，您可以使用field.getType()来确定数据类型。

此处提供了Long或long（基元）类型字段的示例：Check type of primitive field

Answer 2

感谢Eric给出的提示，我找到了一个可以解决更多问题的解决方案。对象：

public static JobParametersBuilder getAttributesAsJobParameters(Object objectToConvert) throws IllegalAccessException {
    JobParametersBuilder jobParametersBuilder = new JobParametersBuilder().addLong("time", System.currentTimeMillis());

    for (Field field : objectToConvert.getClass().getDeclaredFields()) {
        field.setAccessible(true); // We need this to access to attributes if they are private
        if (!field.getType().isPrimitive()) {
            jobParametersBuilder = getAttributesAsJobParameters(field.get(objectToConvert));
        } else {
            matchJobParametersType(jobParametersBuilder, field, objectToConvert);
        }
    }
    return jobParametersBuilder;
}

public static void matchJobParametersType(JobParametersBuilder jobParametersBuilder, Field fieldOfObject, Object object) throws IllegalAccessException {
    String dataTypeOfField = fieldOfObject.getType().getSimpleName();

    switch (dataTypeOfField) {
        case "long":
            jobParametersBuilder.addLong(fieldOfObject.getName(), (Long) fieldOfObject.get(object));
            break;
        case "String":
            jobParametersBuilder.addString(fieldOfObject.getName(), (String) fieldOfObject.get(object));
            break;
        default:
            throw new JobParametersException("Data type " + dataTypeOfField + " not defined");
    }

}

如何为任何对象创建JobParameterBuilder？

2 个答案: