Question

import random
actions = ["act1","act2","act3","act4",
"act5","act6"]
subjects =[,"sub1","sub2","sub3",
"sub4","sub5","sub6"]
s1 = len(actions)
s2 = len(subjects)
num = 0
while True:
    if num < (s1*s2)+1:
        num += 1
        actions += subjects
        print(random.sample(actions+subjects,3))

我想用组合对2个列表进行排序，但是当我打印这个代码时，有些输出有时打印相同的动作或子（例如：[act1，act1，sub5]），但我不想这样做。

我希望每个输出都不同，如果组合结束，它应该停止打印。和我想要的其他东西一样，它为每个输出提供数字。例如：第1行：[act1，sub3，act，4] 第2行：2. [act2，sub2，act1] ... .... ....

我该怎么做？

Answer 1

我不确定followind代码是否是您正在寻找的内容，请查看：

import itertools

actions = ["act1","act2","act3","act4","act5","act6"]
subjects =["sub1","sub2","sub3","sub4","sub5","sub6"]

comb = map(' '.join, itertools.chain(itertools.product(actions, subjects)))

i = 0
for element in comb:
    print("{}. {}".format(i, element))
    i += 1

如何在列表中选择不同的项目并为每个输出添加一个数字？

1 个答案: