Question

这是我的代码

$stmt = $conn->prepare("SELECT tmdb_movies.movie_title,tmdb_movies.tmdb_id, count (tmdb_id),GROUP_CONCAT(DISTINCT genres.genres_name) AS genres_name

FROM tmdb_movies

JOIN genres USING (tmdb_id)

GROUP BY tmdb_movies.movie_title,tmdb_movies.tmdb_id

HAVING find_in_set('$category1', genres_name) AND find_in_set('$category2', genres_name) 

LIMIT $limit OFFSET $start"); 


     // Then fire it up
     $stmt->execute();

 // Pick up the result as an array
 $result = $stmt->fetchAll();

由于我无法在同一代码中计算包含$category1和$category2的总行数，因此我在此之前添加了此代码。

$sql = "SELECT count(tmdb_id),group_concat(genres.genres_name) AS genres_name

 FROM `tmdb_movies` 

JOIN genres USING (tmdb_id)
GROUP BY tmdb_movies.tmdb_id
HAVING find_in_set('$category1', genres_name) AND find_in_set('$category2', genres_name) "; 

$result = $conn->prepare($sql); 
$result->execute(); 
$totalrows = $result->rowCount();
echo $totalrows;

但$totalrows在这里回复3。但是他们的行数要多于3个。

Answer 1

使用fetchAll（）

执行后，您将覆盖$ stmt

所以请尝试这个

$stmt->execute();
 $totalrows = $stmt->rowCount(); 
 echo $totalrows;
 // Pick up the result as an array
 $result = $stmt->fetchAll();

Answer 2

尝试使用rowCount（）计算行数

$totalrows = $stmt->rowCount();

Answer 3

试试这个

$stmt = $conn->prepare("SELECT SQL_CALC_FOUND_ROWS tmdb_movies.movie_title,tmdb_movies.tmdb_id, count (tmdb_id),GROUP_CONCAT(DISTINCT genres.genres_name) AS genres_name

FROM tmdb_movies

JOIN genres USING (tmdb_id)

GROUP BY tmdb_movies.movie_title,tmdb_movies.tmdb_id

HAVING find_in_set('$category1', genres_name) AND find_in_set('$category2', genres_name) 

LIMIT $limit OFFSET $start"); 


     // Then fire it up
     $stmt->execute();

 // Pick up the result as an array
 $result = $stmt->fetchAll();
 $conn->prepare('SELECT FOUND_ROWS() as COUNT');
 $conn->execute();
 $count = $conn->fetchColumn();
 echo $count; //here's your total count

如何计算MySQL表中的行数（PHP PDO）

3 个答案: