Question

这是我选择和回显数据的代码

  <!DOCTYPE html>
<html lang="en">
<head>
    <title>Title</title>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link rel="stylesheet" href="{{ url_for('static', filename='css/bootstrap.min.css') }}">
    <link rel="stylesheet" href="{{ url_for('static',filename='css/style.css') }}">
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
    <link rel="stylesheet" href="http://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css" />
    <script src="http://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
    <script src="{{ url_for('static', filename='js/bootstrap.min.js') }}"></script>   
    <script src="https://js.stripe.com/v3/"></script>
    <script src="{{ url_for('static',filename='js/stripe-local.js') }}"></script>
    <link href="https://fonts.googleapis.com/css?family=Lora:700i|Titillium+Web" rel="stylesheet">
</head>
<body>
    <nav class="navbar navbar-inverse navbar-default navbar-fixed-top">
            <ul class="nav navbar-nav">
            <li class=><a href="#home">Home</a></li>    
            <li><a href="#about">About</a></li>
            <li><a href="#contact">Contact</a></li>
            <li><a href="#pay">Pay</a></li>
            </ul>
    </nav>
    <div class="jumbotron" id="home">
        <div class="container-fluid">
            <h1>Design Something</h1>
        </div>
    </div>
    <div class="container-fluid" id="about">
        <div class="row">
            <h1 class="anchor">About</h1>
            <img src="{{ url_for('static', filename='img/img.jpg') }}" class="img-rounded center-block"></img>
            <div class="container">
            <p>blah blah blah blah blah</p>
            </div>
        </div>
    </div>
    <div class="container-fluid" id="contact">
        <div class="row">
            <h1 class="anchor">Contact Me</h1>  
            <p>email@address.com</p>    
        </div>
    </div>
    <div class="container-fluid" id="pay">
    <h1 class="anchor">Pay Now</h1>
    <a href="#popupPay" data-rel="popup" class="ui-btn ui-btn-inline ui-corner-all ui-icon-check ui-btn-icon-left">Pay Now</a>
        <div data-role="popup" id="popupPay" class="ui-content" style="min-width:250px;">       
            <form method="post" action="charge.py">
                <div>
                    <h3>Payment Form</h3>   
                    <label for="name" class="ui-hidden-accessible">Name:</label>
                    <input type="text" name="name" id="name" placeholder="name">
                    <input type="submit" data-inline="true" value="Pay $">
                    <div class="outcome">
                        <div class="error" role "alert"></div>
                        <div class="success">
                        Success! Your Stripe token is <span class="token"></span>   
                        </div>  
                    </div>  
                </div>  
            </form>
        </div>
    </div>
</body>
</html>

我有2张桌子

1。）Select maintable.movie_title, group_concat(genres.genres_name) AS genres_name FROM maintable JOIN genres USING (tmdb_id) GROUP BY maintable.tmdb_id,maintable.movie_title HAVING find_in_set('$category1', genres_name) AND find_in_set('$category2', genres_name) LIMIT $limit OFFSET $start // Then fire it up $stmt->execute(); // Pick up the result as an array $result = $stmt->fetchAll();

2。）maintable表

两个表都使用genres

相互链接

（请不要询问展示，我尝试了什么。相信我，这会让问题更加混乱）

Answer 1

如果你还需要$ totalrows的数量，它有$ category1和$ category2 您应该使用where in子句

  Select maintable.movie_title, group_concat(genres.genres_name) AS genres_name, count(*) as total_rows
  FROM maintable
  JOIN genres USING (tmdb_id)
  where genres.genres_name in ('$category1', '$category2' )
  GROUP BY maintable.tmdb_id, maintable.movie_title

   LIMIT $limit OFFSET $start

如果你只需要tital_rows，你只能选择这个值（并使用$ totalrows = $ result-＆gt; fetchColumn（）;）或者在这个fecth第2列使用

 $totalrows = $result->fetchColumn(2);

或使用fetchAll

$result = $stmt->fetchAll();

foreach($result as $key=>$row){

  echo $row['total_rows']  ;

}

Answer 2

你想要这个吗？

if ($stmt = $mysqli->prepare($query)) {

    /* execute query */
    $stmt->execute();

    /* store result */
    $stmt->store_result();

    printf("Number of rows: %d.\n", $stmt->num_rows);

    /* close statement */
    $stmt->close();
}

计算MySQL表中的行数（PHP）

2 个答案: