显示MySQL的特定PHP数组

Question

现在MySQL结果中的所有列都转换为JSON并在屏幕上打印出来。我想在屏幕上只打印两列$row['name']和$row['gender']。任何想法的人

include('connect-db.php');

$result = mysql_query("SELECT * FROM patientvaccinedetail")


while($row = mysql_fetch_assoc( $result)) {

print_r(json_encode($row));}

Answer 1

Application.SendKeys("%s")

Answer 2

这是我从表中获取所有内容并仅显示两个值的解决方案....

include('connect-db.php');    
$result = mysql_query("SELECT * FROM patientvaccinedetail") //getting all the fields    

while($row = mysql_fetch_assoc( $result)) {
    $data = array('name' => $row['name'] , 'gender' => $row['gender']); //get the two values into one array

print_r(json_encode($data)); //printing the name and gender
}

如果你只想在这里得到另外两个字段...

include('connect-db.php');    
$result = mysql_query("SELECT name,gender FROM patientvaccinedetail") //getting two the fields    

while($row = mysql_fetch_assoc( $result)) {     

print_r(json_encode($row)); //printing the name and gender
}

Answer 3

如果您想要所有数据，但只需要打印名称＆amp;性别然后..创建一个单独的阵列＆amp;分配名称＆amp;性别...

$data_array = array();
while($row = mysql_fetch_assoc( $result)) {
 array_push($data_array,array("name"=>$row['name'],"gender"=>$row['gender']);
}
print_r(json_encode($data_array));

Answer 4

include('connect-db.php');

$result = mysql_query("SELECT name,gender FROM patientvaccinedetail")


while($row = mysql_fetch_assoc( $result)) {

print_r(json_encode($row));}