我有一个类似下面的查询,我遇到了使用别名变量的问题。
我有错误 mysqli_error()预计只有1个参数,0
SELECT
msg_id, user_first_name, user_last_name, msg_datetime, msg_mrs, msg_of,
msg_telephone, msg_mobile, msg_email, type_description, msg_opt_urgent,
msg_opt_confidential, msg_opt_archived, msg_message,
for_users.user_first_name AS for_user_fn,
for_users.user_last_name AS for_user_ln,
from_users.user_first_name_fn AS from_user_fn,
from_users.user_first_name_ln AS from_user_ln
FROM
messages
LEFT JOIN
users AS for_users ON user_id = msg_for_id
LEFT JOIN
users AS from_users ON user_id = msg_from_id
LEFT JOIN
message_contact_type ON type_id = msg_contact_type_id
WHERE
msg_id = $msg_id
这里的表格
TBL USERS
user_id
user_first_name
user_last_name
TBL MESSAGES
message_id
message_from_id
message_for_id
message_text
我想得到这些变量
$message_from_fn = $row['from_user_fn'];
$message_from_ln = $row['from_user_ln'];
$message_for_fn = $row['for_user_fn'];
$message_for_ln = $row['for_user_ln'];