C bsearch总是返回指针= NULL

时间:2017-06-29 20:04:20

标签: c pointers struct bsearch

有人能告诉我为什么在这个程序中bsearch功能总是返回指针= NULL ??

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct data
{
    char name[10];
    int age;
    char eye[15];
};



int komparator (const void* a, const void *b)
{
    struct data *aa = (struct data *)a;
    struct data *bb = (struct data *)b;
    return (aa->age-bb->age);
}

int main ()
{
    char *NAME[10]={"Ola","Tola","Jola","Zosia","Jan","Adam","Ala","Basia","Tom","Jacek"};
    char *COLOR[10]={"zielone", "brazowe", "niebieskie", "niebieskie", "zielone", "brazowe", "brazowe", "niebieskie", "czarne", "niebieskie"};

    struct data (*pointer)[5];
    struct data people[2][5];
    pointer=people;

    int i;
    for(i=0;i<2*5;i++)
    {
        strcpy((*pointer)[i].name,NAME[i]);
        strcpy((*pointer)[i].eye,COLOR[i]);
        (*pointer)[i].age=rand()%(40-18)+18;
    }

    qsort(people,2*5,sizeof(struct data),komparator);

 // here is the problem:        
    int wanted = 18;
    struct data *found=(struct data*) bsearch(&wanted,people,2*5,sizeof(struct data),komparator);

    if(found!=NULL)
    {
        printf("Found name is: %s,  eye's: %s, age: %d\n",found->name,found->eye,found->age);
    }
    else
    {
        printf("Didnt find \n");
    }
    return 0;
}

请关注bsearch的部分,因为其他方面运作良好。

我将非常感激:)

1 个答案:

答案 0 :(得分:1)

这个问题的解决方案是komparator需要类型(struct data *),所以

int wanted=18;

是错误,在将其更改为

之后
struct data wanted = {"", 18, ""};

一切正常:)

@BLUEPIXY帮助:)