Question

任何人都可以告诉我如何找出Oracle中表中的第N个最大条目吗？

对于最大的我们可以使用 MAX（column_name）是否有任何有效的方法来找到第n个最大的？

Answer 1

SELECT *
FROM (
  SELECT some_column, 
         row_number() over (order by your_sort_column desc) as row_num
  FROM some_table
) t
WHERE row_num = 3

如果您希望在your_sort_column中有多个行具有相同的值，则还可以使用rank（）函数

SELECT *
FROM (
  SELECT some_column, 
         rank() over (order by your_sort_column desc) as row_rank
  FROM some_table
) t
WHERE row_rank = 3

这个migh返回多行..

Answer 2

您可以使用以下查询

找到列的第n个最大值

SELECT * FROM TableName a WHERE 
n = (SELECT count(DISTINCT(b.ColumnName))
FROM TableName b WHERE a.ColumnName <=b.ColumnName);

Answer 3

我认为以下查询可以找到NOT IN的第二高记录。

SELECT MAX( userId )FROM table WHERE userId NOT IN (SELECT MAX( userId )FROM table)

简单实用......

Answer 4

获得第二大薪水使用此：

select salary from 
  (select s2.salary,rownum rm from
     (select distinct salary from employees order by salary desc)
  s2 where rownum<=2)
where rm >= 2

Answer 5

它适用于第二高薪，

$query = "SELECT * FROM `table_name` ORDER BY field_name` DESC LIMIT 1 , 1 ";

Answer 6

您可以ORDER BY column name然后LIMIT 1,1获取第二个

修改

哎呀，没看到Oracle标签，抱歉 ORDER BY column name WHERE ROWNUM = 2应该会更好。

Answer 7

SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (
  SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal
);

将&N替换为您想要的号码。例如，2将为您提供第二大薪水。

如果您正在使用PL / SQL，只需执行该语句即可。它会提示N.

Answer 8

试试这个，

SELECT Sal FROM Tab ORDER BY Sal DESC LIMIT 2,1

Answer 9

试试这个：

SELECT DISTINCT TOP 3 id,[Password] 
FROM Users_changepassword 
WHERE [UserId] = 3
ORDER BY id DESC

Answer 10

你可以尝试使用oracle sql的Row_number（）函数的这个sql

select column_name from (
 select column_name ,  
row_number() over (order by column_name  desc) as  row_num  
from table_Name ) tablex
where row_num =3

Answer 11

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Answer 12

您可以使用CONNECT BY PRIOR：

CREATE TABLE t(i INT, sal INT);
INSERT INTO t(i, sal)
SELECT 1,100 FROM dual UNION
SELECT 2,100 FROM dual UNION
SELECT 3,200 FROM dual UNION
SELECT 4,500 FROM dual UNION
SELECT 5,1000 FROM dual;

查询：

SELECT level, MAX(sal) AS sal
FROM t
--WHERE level = 2 -- set position here
CONNECT BY prior sal > sal
GROUP BY level
ORDER BY level;

<强> DBFiddle Demo

<强> DBFiddle Demo2

修改

第二种方法是使用NTH_VALUE分析函数：

SELECT DISTINCT NTH_VALUE(sal, 2) OVER(ORDER BY sal DESC ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) FROM t;

<强> DBFiddle Demo3

如何从表中获得第二大或第三大条目

12 个答案: