Question

我正在建立一个大学数据库。在管理页面中，我给出了一个选项，如果从下拉菜单中选择了任何程序，将显示在特定程序中注册的所有学生的详细信息。例如，如果用户选择＆＃34;业务管理＆＃34;从下拉菜单中按下提交按钮，所有注册业务管理程序的学生的详细信息都会显示在一个表格中。下面是我编写的代码，但它不起作用。

<?php

$con=mysqli_connect("localhost","root","")or die("conection error");
mysqli_select_db($con,"hamdard university")or die("dbase error");


if(isset($_POST['sub']))

{
  $p=$_POST['selprog'];
  $sql="SELECT * from admission_form where program=$p";
  $result=mysqli_query($con, $sql);

  echo  "<table border=1>
      <th>RollNo</th>
      <th>First Name</th>
      <th>Middle Name</th>
      <th>Last Name</th>
      <th>Address</th>
      <th>Contact</th>
      <th>Faculty</th>
      <th>Major</th>
      <th>Payment</th>";

while($row=mysqli_fetch_array($result, MYSQLI_ASSOC))
{ 
  echo "<tr>";

  echo "<td>";
  echo $row['RollNo'];
  echo "</td>";

  echo "<td>";
  echo $row['firstname'];
  echo "</td>";

  echo "<td>";
  echo $row['middlename'];
  echo "</td>";

  echo "<td>";
  echo $row['lastname'];
  echo "</td>";

  echo "<td>";
  echo $row['address'];
  echo "</td>";

  echo "<td>";
  echo $row['contact'];
  echo "</td>";

  echo "<td>";
  echo $row['major'];
  echo "</td>";

  echo "<td>";
  echo $row['payment'];
  echo "</td>";

}
}

?>

<html>
<head>
<title>Admin</title>
</head>

<body>
<h2>Fetch Student Data</h2><br>
<form name="f1" action="" method="POST">

<h3>Data by Program</h3>
Program:<select name="selprog">

<option value="Business Management">Business Managemen</option>
<option value="Liberal Arts">Liberal Arts</option>
<option value="Performing Arts">Performig Arts</option>
<option value="Journalism">Journalism</option>
<option value="Economics">Economics</option>
</select><br>

<input type="submit" value="Fetch Data" name="sub">

</form>
</body>
</html>

Answer 1

ChildComponents

或者你可以把它变成一个函数并将它放在html代码的中间并摆脱那个echo <?php $conn = new mysqli('localhost', 'username', 'password', 'database') or die ('Cannot connect to db'); $result = $conn->query("select id, name from table"); echo "<html>"; echo "<body>"; echo "<select name='id'>"; while ($row = $result->fetch_assoc()) { unset($id, $name); $id = $row['id']; $name = $row['name']; echo '<option value="'.$id.'">'.$name.'</option>'; } echo "</select>"; echo "</body>"; echo "</html>"; ?>以及所有

从我的sql到下拉列表中选择

1 个答案: