我使用oracle apex创建了一个应用程序。
有没有办法让表格单元格根据单元格内的内容显示不同的链接?
所以我希望有一个图标'+'链接到空单元格内的'创建'页面。
这是apex的互动报告。
但我已将资产列设置为“编辑”页面的链接
以下是生成数据的代码:
select ID,
(SELECT distinct listagg(v.asset_id,', ') within group (order by s.id) from subnet_lookup l, infra_assets_master v where l.subnet_id = s.id AND l.link_id = v.id AND l.def_id = 3) as Assets,
(SELECT distinct listagg(v.hostname,', ') within group (order by s.id) from subnet_lookup l, infra_assets_master v where l.subnet_id = s.id AND l.link_id = v.id AND l.def_id = 3) as Hostname,
(SELECT distinct listagg(m.hostname,', ') within group (order by s.id) from subnet_lookup l, servers_master m where l.subnet_id = s.id AND l.link_id = m.id AND l.def_id = 1) as Servers,
from subnet s
where NETWORK_ID = :P55_NETWORK_ID
ORDER BY ID desc
有没有办法可以设置一个条件,根据单元格内的值显示不同链接的不同信息?