另一个例子

Question

我想从导航堆栈中删除Previous视图控制器。

例如

- ＆GT; A是根视图。现在导航到B-b导航到c-c导航到c-c导航到c

- ＆GT;现在我要删除所有c视图控制器＆amp;弹出到B

B不是修复视图控制器。

另一个例子

A - ＆gt; b - ＆gt; c> g> c> f> c> c> c> ç

从导航中删除所有c视图控制器＆amp;需要关注输出

A - ＆gt; b - ＆gt; c> g> c> f

请帮帮我

Answer 1

从导航堆栈中识别控制器。然后弹出那个控制器

  NSArray *viewControllers = [[self navigationController] viewControllers];
  int count = [viewControllers count];

  for (int i= count-2; i >= 0 ; i--) {

        id obj=[viewControllers objectAtIndex:i];

        if(![obj isKindOfClass:[C class]]){
           [[self navigationController] popToViewController:obj animated:YES];
            return;
        }
   }

Answer 2

您可以使用popToViewController（https://developer.apple.com/documentation/uikit/uinavigationcontroller/1621871-poptoviewcontroller）。

示例：

目标C

[self.navigationController popToViewController:self.navigationController.viewControllers[your_VC_index] animated: true]; 
// in first eg your_VC_index will be 1 and another example it will be 5

在Swift 3中

self.navigationController.popToViewController( self.navigationController.viewControllers[your_VC_index], animated: true)

Answer 3

反向迭代导航堆栈并获取第一个非匹配viewController的索引，然后获取popToViewController

if let controllers = self.navigationController?.viewControllers {
   var count = controllers.count - 1
   for viewcontroller in controllers.reversed() {
       if viewcontroller is CViewController {
          count -= 1
       } else {
          break
       }
    }

    let vc = controllers[count]
    self.navigationController?.popToViewController(vc, animated: true)
 }

Answer 4

编写类似以下的方法，

- (void)removeAllLastCObjectsFromNavigationController {
    //fetch viewcontroller array. for your case which will be A - > b -> c > g > c > f > c > c > c > c
    NSArray *viewControllers = yourNavigationController.viewControllers;
    NSMutableArray *mutableArray = [NSMutableArray arrayWithArray: viewControllers];

    while(1) {
        id viewController = mutableArray.lastObject;
        if ([viewController isKindOfClass:[YourCClassName class]]) {
            //Now continue removing the objects from the array if that is C type object.
            [mutableArray removeLastObject];
        } else {
            //If found any other class than C stop removing viewcontroller
            break;
        }
    }
    //Now mutableArray contains A - > b -> c > g > c > f
    yourNavigationController.viewControllers = mutableArray;
}

Answer 5

因为navigationController的childViewControllers是一个堆栈，所以所以使用这个函数，你可以弹出到f viewController，“c＆gt; c＆gt; c＆gt; c”被破坏。

for (UIViewController *tempVC in self.navigationController.childViewControllers) {
    if ([tempVC isKindOfClass:[fViewController class]]) {
        fViewController *f = (fViewController *)tempVC;
        [self.navigationController popToViewController:f animated:YES];
    }
}

但是，如果你不想弹出到f，只想获得navigationController的新的childViewControllers。你可以使用下一个功能：

for (UIViewController *tempVC in self.navigationController.childViewControllers) {
    if ([tempVC isKindOfClass:[ScanViewController class]]) {
        NSUInteger findex = [self.navigationController.childViewControllers indexOfObject:tempVC];
        NSMutableArray *viewArray = [NSMutableArray arrayWithArray:self.navigationController.childViewControllers];
        [viewArray removeObjectsInRange:NSMakeRange(findex, viewArray.count - 1)];
    }
}

viewArray是新的childViewControllers。如果你有新的需求，可以编辑这个函数然后使用它。

如何从导航控制器ios中删除Previous View Controller？

另一个例子

5 个答案: