我需要将图片大小调整为150 x 150像素,然后将其上传到Amazon S3
以下是代码:
$image = $_FILES["userImage"]["name"];
$fileTempName = $_FILES['userImage']['tmp_name'];
$new_width = 150;
$new_height = 150;
$image_p = imagecreatetruecolor($new_width, $new_height);
$image = imagecreatefromstring(file_get_contents($fileTempName));
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, imagesx($image), imagesy($image));
$newFielName = tempnam(sys_get_temp_dir(), "tempfilename");
imagepng($image_p, $newFielName, 9);
$s3 = new S3(awsAccessKey, awsSecretKey);
//move the file
if ($s3->putObjectFile($fileTempName, "urimages", $newFielName, S3::ACL_PUBLIC_READ)) {
$image_link = 'https://s3-us-west-2.amazonaws.com/urimages/' . $newFielName . '';
$this->Product->saveField('image', $image_link);
}
以下是我在上传时收到的链接:https://s3-us-west-2.amazonaws.com/urimages/C:/Users/LS/AppData/Local/Temp/9102.tmp
可以请你帮我调试代码
答案 0 :(得分:0)
我认为路径问题。请在s3上创建文件夹并使其有效 根据该文件夹的路径
https://s3-us-west-2.amazonaws.com/urimages/C:/Users/LS/AppData/Local/Temp/9102.tmp
Example :- Resampling an image proportionally
<?php
// The file
$filename = 'test.jpg';
// Set a maximum height and width
$width = 200;
$height = 200;
// Content type
header('Content-Type: image/jpeg');
// Get new dimensions
list($width_orig, $height_orig) = getimagesize($filename);
$ratio_orig = $width_orig/$height_orig;
if ($width/$height > $ratio_orig) {
$width = $height*$ratio_orig;
} else {
$height = $width/$ratio_orig;
}
// Resample
$image_p = imagecreatetruecolor($width, $height);
$image = imagecreatefromjpeg($filename);
imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig);
// Output
imagejpeg($image_p, null, 100);
?>