您好我是android的初学者。我想在我的电脑上建立数据库连接到mssql服务器。我在网上找到了例子。 我想我连接有问题。因为我的User表中有两条记录。但是这段代码只给了我表中的第一条记录。
这是ConnectionClass.java:
import android.annotation.SuppressLint;
import android.os.StrictMode;
import android.util.Log;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.SQLException;
public class ConnectionClass {
String ip = "127.0.0.1:1433";
String classs = "net.sourceforge.jtds.jdbc.Driver";
String db = "DBAndroid1";
String un = "TestUser";
String password = "123";
@SuppressLint("NewApi")
public Connection CONN() {
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
.permitAll().build();
StrictMode.setThreadPolicy(policy);
Connection conn = null;
String ConnURL = null;
try {
Class.forName(classs).newInstance();
ConnURL = "jdbc:jtds:sqlserver://" + ip + ";"
+ "databaseName=" + db + ";user=" + un + ";password="
+ password + ";";
conn = DriverManager.getConnection(ConnURL);
} catch (SQLException se) {
Log.e("ERRO0", se.getMessage());
} catch (ClassNotFoundException e) {
Log.e("ERRO1", e.getMessage());
} catch (Exception e) {
Log.e("ERRO2", e.getMessage());
}
return conn;
}
}
这是我的MainActivity.java。
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ProgressBar;
import android.widget.Toast;
import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.Statement;
import java.util.ArrayList;
public class MainActivity extends AppCompatActivity {
ConnectionClass connectionClass;
EditText edtuserid, edtpass;
Button btnlogin;
ProgressBar pbbar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
connectionClass = new ConnectionClass();
edtuserid = (EditText) findViewById(R.id.et_username);
edtpass = (EditText) findViewById(R.id.et_password);
btnlogin = (Button) findViewById(R.id.btn_Login);
pbbar = (ProgressBar) findViewById(R.id.pbbar);
pbbar.setVisibility(View.GONE);
btnlogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
DoLogin doLogin = new DoLogin();
doLogin.execute("");
}
});
}
public class DoLogin extends AsyncTask<String,String,String>
{
String z = "";
Boolean isSuccess = false;
String userid = edtuserid.getText().toString();
String password = edtpass.getText().toString();
@Override
protected void onPreExecute() {
pbbar.setVisibility(View.VISIBLE);
}
@Override
protected void onPostExecute(String r) {
pbbar.setVisibility(View.GONE);
Toast.makeText(MainActivity.this,r,Toast.LENGTH_SHORT).show();
if(isSuccess) {
Toast.makeText(MainActivity.this,r,Toast.LENGTH_SHORT).show();
}
}
@Override
protected String doInBackground(String... params) {
if(userid.trim().equals("")|| password.trim().equals(""))
z = "Please enter User Id and Password";
else
{
try {
Connection con = connectionClass.CONN();
if (con == null) {
z = "Error in connection with SQL server";
} else {
String query = "select Username from [User]";
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(query);
int columnCount = rs.getMetaData().getColumnCount();
System.out.println("Eleman sayisi: "+ columnCount);
if(rs.next())
{
String lastName = rs.getString("Username");
z = "Login successfull";
z = z + " " + lastName;
isSuccess=true;
}
else
{
z = "Invalid Credentials";
isSuccess = false;
}
}
}
catch (Exception ex)
{
isSuccess = false;
z = "Exceptions burda mi "+ ex;
}
}
return z;
}
}
}
我希望你能提供帮助。谢谢。
答案 0 :(得分:1)
您在表中有两条记录但是您使用if(rs.next())来获取仅返回单条记录的记录。 使用循环或while循环来获取所有记录并循环迭代结果集。