Question

我想要某种错误处理，如果语句以错误执行，则设置布尔变量false 或者如果它没有错误地运行，则设置布尔值为真

在我的情况下，我的代码是

$response = array();
$response["success"] = true;

$statement = $mysqli->prepare("INSERT INTO userft (name, username, pasword, email, contact, age) VALUES (?, ?, ?, ?, ?, ?)");
$statement->bind_param('ssssii', $name, $username,$pasword,$email,$contact, $age);
$statement->execute();

if(!($statement->execute())){   //<----- in replace of this statement?<-----
$response["success"]=false;}

Answer 1

如果将execute语句返回值分配给变量，则可以测试成功/失败。

$response = array('success'=>false);


$stmt = $mysqli->prepare("INSERT INTO userft (name, username, pasword, email, contact, age) VALUES (?, ?, ?, ?, ?, ?)");
/* First test that the statement was prepared successfully */
if( $stmt ){
    $stmt->bind_param('ssssii', $name, $username,$pasword,$email,$contact, $age);

    /* assign return value of execute to a variable */
    $status = $stmt->execute();

    /* use variable to determine response */
    $response["success"]=$status ? true : false;
}

您可以在prepared statements

上详细了解PHP site

Answer 2

execute语句返回boolean，所以你做的是正确的事;您可以将结果分配给变量：

$success = $statement->execute();
if ($success) {
    echo "Inserted!";
} else {
    echo "Something went wrong!";
}

如有疑问，请查看documentation。

Answer 3

试试这个

$statement->execute();
if ($statement->affected_rows()) {
         //success
} else {
   die('execute() failed: ' . $mysqli->error);
}

如何检查语句执行错误或没有错误？

3 个答案: