我有以下卷曲请求:
curl -X GET http://hostname:4444/grid/api/hub -d '{"configuration":["slotCounts"]}'
返回一个JSON对象。
如何在Java中提出此类请求并获得响应?我试过这个:
URL url = new URL("http://hostname:4444/grid/api/hub -d '{\"configuration\":[\"slotCounts\"]}'");
try (BufferedReader reader = new BufferedReader(new InputStreamReader(
url.openStream(), "UTF-8"))) {
for (String line; (line = reader.readLine()) != null;) {
System.out.println(line);
}
}
但它返回一个例外:
Caused by: java.io.IOException: Server returned HTTP response code: 400 for URL: http://hostname:4444/grid/api/hub -d '{"configuration":["slotCounts"]}'
答案 0 :(得分:2)
根据评论,设法自己解决。
private static class HttpGetWithEntity extends
HttpEntityEnclosingRequestBase {
public final static String METHOD_NAME = "GET";
@Override
public String getMethod() {
return METHOD_NAME;
}
}
private void getslotsCount() throws IOException,
URISyntaxException {
HttpGetWithEntity httpEntity = new HttpGetWithEntity();
URL slots = new URL("http://hostname:4444/grid/api/hub");
httpEntity.setURI(pendingRequests.toURI());
httpEntity
.setEntity(new StringEntity("{\"configuration\":[\""
+ PENDING_REQUEST_COUNT + "\"]}",
ContentType.APPLICATION_JSON));
HttpClient client = HttpClientBuilder.create().build();
HttpResponse response = client.execute(getPendingRequests);
BufferedReader rd = new BufferedReader(new InputStreamReader(response
.getEntity().getContent()));
// At this point I can just get the response using readLine()
System.out.println(rd.readLine());
}
答案 1 :(得分:-1)
这不是Java中发送数据的方式。 -d标志仅用于CURL CLI。在Java中,您应该使用像Apache HTTP Client这样的库: https://stackoverflow.com/a/3325065/5898512
然后使用JSON解析结果:https://stackoverflow.com/a/5245881/5898512
答案 2 :(得分:-1)
根据您的异常/错误日志,它清楚地表明服务http://hostname:4444/grid/api/hub
正在接收错误请求(状态代码400)。
我认为您需要检查您正在接受的服务以及它接受的内容。例如:该服务可能只接受application/json
/ application/x-www-form-urlencoded
或服务期望但不发送的参数。