Laravel访问其他函数的变量

Question

我有一个- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer { return YES; } - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch { return YES; } - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceivePress:(UIPress *)press { return YES; } 方法，我必须向sendOtp()方法发送otp用于更改密码的方法

我想将changePassword()从$otp返回到sendOtp()

changePassword()方法

sendOtp

public function sendOtp($user_phone_number) { $otp = mt_rand(100000, 999999); //sms login $data = [ 'data' => [ 'otp' => $otp ] ]; return Response::json( $data_with_status = array_merge($this->respondSuccess('otp sent'), $data) ); } 方法

changePassword()

谢谢

Answer 1

您可以通过以下代码收到otp：

public function changePasswordOtp($user_phone_number)
{
    $user = User::where('phone_number', '=', $user_phone_number)->count();

    if($user > 0) {

        $result_otp = $this->sendOtp($user_phone_number); 
         $result_otp = json_decode($result_otp ,true);

        $otp = $result_otp['data']['otp']; //return response with sent otp
    }
    else {

        return Response::json(
            $this->respondFailure('User not found')
        );

    }
}

Answer 2

像这样更改sendOtp：

public function sendOtp($user_phone_number)
{
    $otp = mt_rand(100000, 999999); 

    //sms login

    $data = [
        'data' => [
            'otp' => $otp
        ]
    ];
    $responseMessage= $this->respondSuccess();
    $responseArray = array_merge(responseMessage, data);
    return Response::json($responseArray); 
    );
}