Question

我在yii2中使用gii来生成一个crud系统。我需要编写这个sql来过滤表中的正确数据。

$date_now = date('Y-m-d');

$query = "SELECT * FROM reservation_db WHERE STR_TO_DATE(日期,'%d-%m-%Y') > '$date_now'";

我知道这是错的，我将日期保存为数据库中的类型文本。因此，我需要使用STR_TO_DATE将字符串转换为日期，并使sql仅选择比今天更大的数据。

知道我在哪做sql吗？

这是我的ReservationSearch模型

 <?php

 namespace app\models;

 use Yii;
 use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\ReservationDb;

/ ** * ReservationSearch代表搜索表单背后的模型 app\models\ReservationDb。 * / class ReservationSearch扩展ReservationDb { / ** * @inheritdoc * / 公共职能规则（） { 返回[ [['reservation_id'，'成人'，'孩子'，'infat'，'phone_num']， '整数']， [['name'，'date'，'time'，'session'，'seat_area'，'remark'， 'payment_status'，'reservation_date']，'safe']， ]。 }

/**
 * @inheritdoc
 */
public function scenarios()
{
    // bypass scenarios() implementation in the parent class
    return Model::scenarios();
}

/**
 * Creates data provider instance with search query applied
 *
 * @param array $params
 *
 * @return ActiveDataProvider
 */
public function search($params)
{
    $date_now = date('Y-m-d');

    $query = ReservationDb::find();
    $query->andFilterCompare( 'STR_TO_DATE(date)', '$date_now', '>');





    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    $this->load($params);

    if (!$this->validate()) {
        // uncomment the following line if you do not want to return any 
    records when validation fails
        // $query->where('0=1');
        return $dataProvider;
    }

    // grid filtering conditions
    $query->andFilterWhere([
        'reservation_id' => $this->reservation_id,
        'adult' => $this->adult,
        'child' => $this->child,
        'infat' => $this->infat,
        'phone_num' => $this->phone_num,
    ]);

    $query->andFilterWhere(['like', 'name', $this->name])
        ->andFilterWhere(['like', 'date', $this->date])
        ->andFilterWhere(['like', 'time', $this->time])
        ->andFilterWhere(['like', 'session', $this->session])
        ->andFilterWhere(['like', 'seat_area', $this->seat_area])
        ->andFilterWhere(['like', 'remark', $this->remark])
        ->andFilterWhere(['like', 'payment_status', $this->payment_status])
        ->andFilterWhere(['like', 'reservation_date', $this-
      >reservation_date]);

    return $dataProvider;
}

}

Answer 1

试试这个：

public function search($params)
{
   $date_now = date('Y-m-d');

   $query = ReservationDb::find();
   $query->andFilterCompare('STR_TO_DATE(date)', $date_now, '>');
   .
   .
   .
}

Yii2 Gii编写自己的sql来过滤数据

1 个答案: