Question

修改：

使用以下学生的分数文件，我如何加载数据并在Python中总结score1，score3？

{"id": "1","student":"John", "dt": "1997-01-01 07:00:02", "score1": "38.28"} 
{"id": "2", "student":"Jane", "dt": "1997-01-01 07:00:02", "score1": "32.35"} 
{"id": "3", "student":"Richard", "dt": "1997-01-10 10:00:00", "score3": "22.92"}

输出：

score1: 70.63
score3: 22.92

Answer 1

<强> file.txt的：

{"id": "1","student":"John", "dt": "1997-01-01 07:00:02", "score1": "38.28"} 
{"id": "2", "student":"Jane", "dt": "1997-01-01 07:00:02", "score1": "32.35"} 
{"id": "3", "student":"Richard", "dt": "1997-01-10 10:00:00", "score3": "22.92"}

执行：

import json

scores = dict()
with open('file.txt') as filename:
    for line in filename.readlines():
       data = json.loads(line)
       score = [key for key in data.keys() if key.startswith('score')]
       if len(score) == 0:
           continue
       score = score[0]
       if score not in scores:
           scores[score] = 0
       scores[score] += float(data[score])

for k, v in scores.items():
    print('{}: {}'.format(k, v))

输出继电器：

score1: 70.63
score3: 22.92

Answer 2

使用内置库json，您可以将JSON解码为Python对象。如果您使用此数据：

[
    {"id": "1","student":"John", "dt": "1997-01-01 07:00:02", "score1": "38.28"}, 
    {"id": "2", "student":"Jane", "dt": "1997-01-01 07:00:02", "score1": "32.35"}, 
    {"id": "3", "student":"Richard", "dt": "1997-01-10 10:00:00", "score3": "22.92"}
]

请注意数据中的[...]和,，以便将其作为列表加载。

然后下面的脚本可以完成这项工作。

import json
from math import fsum

data = json.load(open("data.json")) # Load the data
sums = {}
for person in data: # Loop over pieces of data
    # Add any names starting with "score" to sums
    for key in person.keys(): # Loop over names
        if not key[:5] == "score":
            continue # No, not starting with score, skip it
        # Use math.fsum to add the value known to the score, and set it.
        sums[key] = fsum([sums.get(key, 0.0), float(person[key])])
for k, v in sums.items():
    # Print out the data
    print("%s: %.02f" % (k, v))

我在评论中添加了解释。在IDLE 3.6.1中测试。

计算循环python分数文件

2 个答案: