如何用最少的代码在c ++中操作嵌套的QJsonObject / QJsonArray结构？

Question

假设我有一个嵌套的QJsonObject，它看起来像下面的JSON：

var sample_set_ = 
  {child_sample_set_objs:[
    {sample_containers:[
      {"samples":[
        {id:1, sample_val:42}
      ]}
    ]}
  ]}

或等效地：

auto sample_set_ = 
  QJsonObject{
    {"child_sample_set_objs",
      QJsonArray{
        { QJsonObject{
          {"sample_containers",
            QJsonArray{
              { QJsonObject{
                {"samples,
                  QJsonArray{
                    { QJsonObject{
                      "id", 1,
                      "sample_val", 42
                    } }
                  }
                }
              }
            } }
          }
        } }
      }
    }
  }

如何将数据写入叶子节点并变异sample_set_而不会一直向上复制结构？

以下是我认为我需要做的事情，这是非常冗长的。

给定int child_ss_idx和int sample_container_idx：

auto child_sample_set_objs = sample_set_["child_sample_set_objs"].toArray();
auto child_ss = child_sample_set_objs[child_ss_idx].toObject();
auto sample_containers = child_ss["sample_containers"].toArray();
auto sample_container = sample_containers[sample_container_idx].toObject();
auto samples = sample_container["samples"].toArray();

// the write vvvvvvvv
samples.push_back(QJsonObject{ {"sample_set_id", child_ss["id"]} });

sample_container["samples"] = samples;
sample_containers[sample_container_idx] = sample_container;
child_ss["sample_containers"] = sample_containers;
child_sample_set_objs[child_ss_idx] = child_ss;
sample_set_["child_sample_set_objs"] = child_sample_set_objs;